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Art [367]
3 years ago
9

An adaptation of an animal in the desert might be to

Physics
1 answer:
expeople1 [14]3 years ago
6 0
Keep cool by being active at night, whereas some other desert animals get away from the sun's heat by digging underground burrows.
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Is a perch a consumer or...
labwork [276]
Yes a perch is a consumer.

8 0
3 years ago
An Olympic runner completes the 200-meter sprint in 23 seconds. What is the runner’s average speed? (Round your answer to the ne
LUCKY_DIMON [66]
The answer that is got 8.7 . I got that because if you divide 200 by 23  you get <span>8.69565217391 and if you round that you get 8.7</span>
5 0
3 years ago
Read 2 more answers
The critical angle for a certain air-liquid surface is 47.7°. What is the index of refraction of the liquid? Round to the neares
KengaRu [80]

Answer:

The index of refraction of the liquid is 1.35.

Explanation:

It is given that,

Critical angle for a certain air-liquid surface, \theta_1=47.7^{\circ}

Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1

Using Snell's law for air liquid interface as :

n_1\ sin\theta_1=n_2\ sin(90)

n_1\ sin(47.7)=1

n_1=\dfrac{1}{sin(47.7)}

n_1=1.35

So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.

5 0
3 years ago
If spring has a spring constant of 500 N/m and is stretched .50 meters,how much energy is stored in the spring ((show work for f
Free_Kalibri [48]

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

k = 500N/m --- spring constant

x = 0.5m --- stretch

Required

The amount of energy

This is calculated as:

U = \frac{1}{2} kx^2

U = \frac{1}{2} * 500N/m * (0.5m)^2

U = 250N/m * (0.5m)^2

U = 62.5\ J

7 0
2 years ago
Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
noname [10]

Answer:

a)   I = 2279.5 N s , b) F = 3.80 10⁵ N, c)   I = 3125.5 N s  and d)  F = 5.21 10⁵ N

Explanation:

The impulse is equal to the variation in the amount of movement.

    I =∫ F dt = Δp

     I = mv_{f} - m v₀

Let's calculate the final speed using kinematics, as the cable breaks the initial speed is zero

   v_{f}² = V₀² - 2g y

   v_{f}² = 0 - 2 9.8 30.0

   v_{f} = √588

   v_{f} = 24.25 m/s

a) We calculate the impulse

   I = 94 24.25 - 0

   I = 2279.5 N s

b) Let's join the other expression of the impulse to calculate the average force

   I = F t

  F = I / t

  F = 2279.5 / 6 10⁻³

  F = 3.80 10⁵ N

just before the crash the passenger jumps up with v = 8 m / s, let's take the moments of interest just when the elevator arrives with a speed of 24.25m/s down and as an end point the jump up to vf = 8 m / n

c)     I = m v_{f} - m v₀

       I = 94 8 - 94 (-24.25)

       I = 3125.5 N s

d)     F = I / t

       F = 3125.5 / 6 10⁻³

       F = 5.21 10⁵ N

7 0
3 years ago
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