A ball is dropped from the top of a building. The distance, y, in meters above the ground for the ball after t seconds can be mo
deled by the equation u=-9.8t^2+100.
1 answer:
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Answer:
- 240
Step-by-step explanation:
We have to find the value of the following determinant
Now, we know that the value of a general determinant is given by [a( ei - fh) + b(fg - di) + c(dh - eg)]
Therefore, the value of the given determinant is
= 4[0 × 4 - (-1)(-2)] + 8[3(-1) - 4 × 4] + 10[4(-2) - 3 × 0]
= - 8 - 152 - 80 = - 240 (Answer)