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3 years ago

12

Which two levels of ecological organization include members of only a single species?

2 answers:

Strike441 [17]3 years ago

5 0

There are six levels of ecological organization, listed from the smallest to the largest, they are: organism, population, community, ecosystem, biome and biosphere.
The two levels which are made up of members of only a single species are ORGANISMS and POPULATION. Organism refers to any individual living thing while population refers to a group of individual species that live in a specific area at a particular time.<span />

s2008m [1.1K]3 years ago

4 0

Answer: Your answer is B Organisms and Population Organism refers to any kind of individual living thing while population refers to a kind of group of individual species that live in a specific area at a particular time.

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What is the name of the compound CH4?<br>

agasfer [191]

Answer:

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Explanation:

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3 years ago

A gas balloon has a volume of 106.0 liters when the temperature is 25.0 °C and the pressure is 740.0 mm Hg. What will its volume

ipn [44]

Answer : The final volume of gas will be, 103.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 740.0 mmHg = 98.4 kPa

Conversion used : (1 mmHg = 0.133 kPa)

$P_2$ = final pressure of gas = 99.3 kPa

$V_1$ = initial volume of gas = 106.0 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $25.0^oC=273+25.0=298K$

$T_2$ = final temperature of gas = $20.0^oC=273+20.0=293K$

Now put all the given values in the above equation, we get:

$\frac{98.4kPa\times 106.0L}{298K}=\frac{99.3kPa\times V_2}{293K}$

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4 years ago

The air in a 4.00 L tank has a pressure of 1.20 atm . What is the final pressure, in atmospheres, when the air is placed in tank

stellarik [79]

Answer:

P₂ = 1.92 atm

Explanation:

According to the boyle's law:

The pressure of given amount of gas at constant temperature and number of moles of gas is inversely proportional to the volume.

P₁V₁= P₂V₂

Given data:

Initial volume = 4.00 L

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Final pressure = ?

Solution:

First of all we will convert the volume into litter.

2500 mL × 1L/1000 mL = 2.5 L

P₁V₁ = P₂V₂

P₂ = P₁V₁ /V₂

1.20 atm×4.00 L = P₂ ×2.5 L

P₂ = 1.20 atm×4.00 L/ 2.5 L

P₂ = 4.8 atm. L/ 2.5 L

P₂ = 1.92 atm

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4 years ago

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Assoli18 [71]

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