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2 years ago

State Boyle's, Charles's, and Gay-Lussac's laws using sentences, then equations

Chemistry

1 answer:

dimaraw [331]2 years ago

7 0

Explanation:

1. Boyle's Law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$ (At constant temperature and number of moles)

$P_1\times {V_1}=P_2\times V_2$

2. Charles' Law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$ (At constant pressure and number of moles

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

3. Gay Lussac's Law states that tempertaure is directly proportional to the pressure of the gas at constant volume and number of moles of gas

$P\propto T$ (At constant volume and number of moles)

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

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2 years ago

The decomposition of ammonia is: 2 NH3(g) ⇌ N2(g) + 3 H2(g). If Kp is 1.5 × 103 at 400°C, what is the partial pressure of ammoni

ValentinkaMS [17]

Answer:

" $6.7\times 10^{-4} \ atm$ " is the right answer.

Explanation:

Given:

Partial pressure of $N_2$ ,

= 0.20 atm

Partial pressure of $H_2$ ,

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$K_p = 1.5\times 10^3$ at $400^{\circ} C$

As we know,

⇒ $K_p = \frac{pN_2\times pH_2^3}{pNH_3^2}$

By putting the values, we get

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2 years ago

A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el

icang [17]

Answer:

The temperature of the air at this given elevation will be 53.32425°C

Explanation:

We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.

Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm ; Final Volume = 1.8 L ; Final pressure = 0.73 atm

We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T $_2$ ),

P $_1$ V $_1$ / T $_1$ = P $_2$ V $_2$ / T $_2$ ,

T $_2$ = P $_2$ V $_2$ T $_1$ / P $_1$ V $_1$ ,

T $_2$ = 0.73 atm $*$ 1.8 L $*$ 298.15 K / 1 atm $*$ 1.2 L = ( 0.73 $*$ 1.8 $*$ 298.15 / 1 $*$ 1.2 ) K = 326.47425 K,

T $_2$ = 326.47425 K = 53.32425 C

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2 years ago