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3 years ago

What is the normality of a solution that contains 1.89g of h2c2o2 2h2oin 1---ml of solution?

Chemistry

1 answer:

garri49 [273]3 years ago

6 0

First convert mass to number of moles. Molar mass of H2C2O2 • 2H2O = 94 / mol

1.89g / (94 g / mol) = .02 mol H2C2O2 • 2H2O

Then we divide by 0.1 L, or 100 mL, and we get a concentration of 0.2 M.

Since there are two positive ions (2 H+), therefore normality is:

0.4 N

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Data Collection

vladimir2022 [97]

Answer:

For a): The mass percent of naphthalene in the original sample is 31.00 %.

For b): The mass percent of 3-nitroaniline in the original sample is 32.03 %.

For c): The mass percent of benzoic acid in the original sample is 29.97 %.

For d): The total percent recovered is 93.00 %.

Explanation:

Percentage by mass is defined as the ratio of the mass of a substance to the mass of the solution multiplied by 100. The formula used for this is:

$\text{Percent by mass}=\frac{\text{Mass of substance}}{\text{Mass of a solution}} \times 100$ ......(1)

a):

Mass of naphthalene = 0.483 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

$\%\text{ mass of naphthalene}=\frac{0.483 g}{1.558}\times 100\\\\\%\text{ mass of naphthalene}=31.00 \%$

b):

Mass of 3-nitroaniline = 0.499 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

$\%\text{ mass of 3-nitroaniline}=\frac{0.499 g}{1.558}\times 100\\\\\%\text{ mass of 3-nitroaniline}=32.03 \%$

c):

Mass of benzoic acid = 0.467 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

$\%\text{ mass of benzoic acid}=\frac{0.467 g}{1.558}\times 100\\\\\%\text{ mass of benozic acid}=29.97 \%$

d):

Total mass recovered = [0.483 + 0.499 + 0.467] = 1.449 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

$\text{Total percent recovered}=\frac{1.449 g}{1.558}\times 100\\\\\text{Total percent recovered}=93.00\%$

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