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nadya68 [22]
3 years ago
5

Data Collection

Chemistry
1 answer:
vladimir2022 [97]3 years ago
8 0

<u>Answer:</u>

<u>For a):</u> The mass percent of naphthalene in the original sample is 31.00 %.

<u>For b):</u> The mass percent of 3-nitroaniline in the original sample is 32.03 %.

<u>For c):</u> The mass percent of benzoic acid in the original sample is 29.97 %.

<u>For d):</u> The total percent recovered is 93.00 %.

<u>Explanation:</u>

Percentage by mass is defined as the ratio of the mass of a substance to the mass of the solution multiplied by 100. The formula used for this is:  

\text{Percent by mass}=\frac{\text{Mass of substance}}{\text{Mass of a solution}} \times 100               ......(1)

a):

Mass of naphthalene = 0.483 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of naphthalene}=\frac{0.483 g}{1.558}\times 100\\\\\%\text{ mass of naphthalene}=31.00 \%

b):

Mass of 3-nitroaniline = 0.499 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of 3-nitroaniline}=\frac{0.499 g}{1.558}\times 100\\\\\%\text{ mass of 3-nitroaniline}=32.03 \%

c):

Mass of benzoic acid = 0.467 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of benzoic acid}=\frac{0.467 g}{1.558}\times 100\\\\\%\text{ mass of benozic acid}=29.97 \%

d):

Total mass recovered = [0.483 + 0.499 + 0.467] = 1.449 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\text{Total percent recovered}=\frac{1.449 g}{1.558}\times 100\\\\\text{Total percent recovered}=93.00\%

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