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nadya68 [22]
3 years ago
5

Data Collection

Chemistry
1 answer:
vladimir2022 [97]3 years ago
8 0

<u>Answer:</u>

<u>For a):</u> The mass percent of naphthalene in the original sample is 31.00 %.

<u>For b):</u> The mass percent of 3-nitroaniline in the original sample is 32.03 %.

<u>For c):</u> The mass percent of benzoic acid in the original sample is 29.97 %.

<u>For d):</u> The total percent recovered is 93.00 %.

<u>Explanation:</u>

Percentage by mass is defined as the ratio of the mass of a substance to the mass of the solution multiplied by 100. The formula used for this is:  

\text{Percent by mass}=\frac{\text{Mass of substance}}{\text{Mass of a solution}} \times 100               ......(1)

a):

Mass of naphthalene = 0.483 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of naphthalene}=\frac{0.483 g}{1.558}\times 100\\\\\%\text{ mass of naphthalene}=31.00 \%

b):

Mass of 3-nitroaniline = 0.499 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of 3-nitroaniline}=\frac{0.499 g}{1.558}\times 100\\\\\%\text{ mass of 3-nitroaniline}=32.03 \%

c):

Mass of benzoic acid = 0.467 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of benzoic acid}=\frac{0.467 g}{1.558}\times 100\\\\\%\text{ mass of benozic acid}=29.97 \%

d):

Total mass recovered = [0.483 + 0.499 + 0.467] = 1.449 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\text{Total percent recovered}=\frac{1.449 g}{1.558}\times 100\\\\\text{Total percent recovered}=93.00\%

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2. Percent by mass of anhydrous Salt (FeSO₄) = 54.7 %

Explanation:

Data Given

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% by mass water (H₂O) = ?

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________________________________________

> First of all find the atomic masses of each component in a molecule

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> Then find the total mass of H₂O in haydrated salt

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_______________________________________________

> First of all find the atomic masses of each component in a molecule

For anhydrus salt (FeSO₄) atomic masses are given below

Fe = 56 g/mol

S= 32 g/mol

O = 16 g/mol

> Then find the total mass of FeSO₄ in haydrated salt

FeSO₄ = (56x1 + 32 + 4x16) g/mol

FeSO₄ = ( 56 + 32 + 64) g/mol

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> find total Molar Mass of Molecule:

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 16x4] + 7(2+16)

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

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Formula used to find the mass by percent of a component

Percent composition of  FeSO₄ = mass of FeSO₄ in Molecule / molar mass of FeSO₄ • 7H₂O x 100%  

Put the values

Percent by mass of FeSO₄ = 152 (g/mol) / 278 (g/mol) x 100%

Percent by mass of FeSO₄ = 0.547 x 100%  

Percent by mass of FeSO₄ = 54.7 %

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