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lyudmila [28]
3 years ago
12

What is the formula for Disulfur Pentafluoride?

Chemistry
1 answer:
dolphi86 [110]3 years ago
7 0

Answer:

please mark me as brainliest so difficulty to find me and edit

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The lightest weight element that is not a gas
LUCKY_DIMON [66]

Answer:Lithium

Explanation:Lithium has 3 protons, and 4 neutrons making it the lightest element that isn't a gas.

5 0
3 years ago
Read 2 more answers
The percent composition of calcium is ?
DochEvi [55]

Answer: 40.1%

Explanation: The mass of calcium in this compound is equal to 40.1 grams because there's one atom of calcium present and calcium has an atomic mass of 40.1 . The molar mass of the compound is 100.1 grams. Using the handy equation above, we get: Mass percent = 40.1 g Ca⁄100.1 g CaCO3 × 100% = 40.1% Ca.

5 0
3 years ago
7. How many moles of mercury(ii) oxide, hgo, are needed to produce 12. 5 g of oxygen, o2? 2 hgo(s) --->2 hg(l) o2(g)
svetoff [14.1K]

Moles are the division of the mass and the molar mass. The moles of mercury (ii) oxide in the decomposition reaction needed to produce oxygen are 0.781 moles.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction is a breakdown of the reactant into simpler products. The decomposition of mercury (ii) oxide can be shown as:

2HgO(s) → 2Hg(l) + O₂(g)

From the reaction, it can be said that 2 moles of mercury (ii) oxide decomposes to produce 1 mole of oxygen.

The moles of oxygen that needs to be produced are calculated as:

Moles = mass ÷ molar mass

= 12.5 gm ÷ 32 gm/mol

= 0.39 moles

0.39 moles of oxygen are needed to be produced.

From the stoichiometric coefficient of the reaction, the moles of HgO is calculated as: 2 × 0.39 = 0.781 moles

Therefore, 0.781 moles of HgO are required in the reaction.

Learn more about moles here:

brainly.com/question/3801333

#SPJ4

5 0
2 years ago
Calculate the mass of water produced when 7.26 g of butane reacts with excess oxygen
MaRussiya [10]

Answer:

11.3 g.

Explanation:

Hello there!

In this case, since the combustion of butane is:

C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

m_{H_2O}=7.26gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}}*\frac{5molH_2O}{1molC_4H_{10}}  *\frac{18.02gH_2O}{1molH_2O}

Therefore, the resulting mass of water is:

m_{H_2O}=11.3gH_2O

Best regards!

4 0
3 years ago
Several ways in which water is an unusual<br> List several ways in<br> substance.
SashulF [63]

Boiling Point and Freezing Point., Surface Tension, Heat of Vaporization, and Vapor Pressure, Viscosity and Cohesion, solid State, Liquid State, Gas State.

4 0
3 years ago
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