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natta225 [31]
4 years ago
9

Which correctly lists the outer planets from the least number of moons to the greatest number of moons?

Physics
2 answers:
Harlamova29_29 [7]4 years ago
6 0
There are two planets with no moons, Mercury and Venus. After that the order<span> is Earth (1), Mars (2), Neptune (14), Uranus (27), Saturn (62), and Jupiter (67).

so its A

</span>
Alex Ar [27]4 years ago
4 0
D) <span>Uranus, Neptune, Jupiter, Saturn

Hope this helped!</span>
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Describe the energy of a playground swing at its highest point
Korvikt [17]
At the hightest point it would be potential energy, because the energy is stored and then when it is rocking back and forth it has kinetic energy
8 0
4 years ago
A force of 14 N acts on a 5 kg object for 3 seconds.
DiKsa [7]

Answer: a) 42Nm b) 8.4m/s

Explanation:

Impulse is defined as object change in momentum.

Since Force = mass × acceleration

F = ma

Acceleration is the rate of change in velocity.

F = m(v-u)/t

Cross multiply

Ft = m(v-u)

Since impulse = Ft

and Ft = m(v-u)... (1)

The object change in velocity (v-u) = Ft/m from eqn 1

Going to the question;

a) Impulse = Force (F) × time(t)

Given force = 14N and time = 3seconds

Impulse = 14×3

Impulse = 42Nm

b) The object change in velocity (v-u) = Ft/m where mass = 5kg

v-u = 14×3/5

Change in velocity = 42/5 = 8.4m/s

3 0
3 years ago
A 0.0140 kg bullet traveling at 205 m/s east hits a motionless 1.80 kg block and bounces off it, retracing its original path wit
makvit [3.9K]

Answer:

Final velocity of the block = 2.40 m/s east.

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum

Mass of bullet = 0.0140 kg

Consider east as positive.

Initial velocity of bullet = 205 m/s

Mass of Block = 1.8 kg

Initial velocity of block = 0 m/s

Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s

Final velocity of bullet = -103 m/s

We need to find final velocity of the block( u )

Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u

We have

            2.87 = -1.442 + 1.8 u

               u = 2.40 m/s

Final velocity of the block = 2.40 m/s east.

7 0
4 years ago
A vinyl record is played by rotating the record so that an approximately circular groove in the vinyl slides under a stylus. Bum
Fed [463]

Answer:

983.400345675 hits per second

Explanation:

Radius = 14.2 cm

Record turn rate = 33 rev/min

Bump separation = 0.499 mm

Circumference of the record = 2\pi 0.142=0.89221231362\ m

Number of bumps in the groove = \dfrac{0.89221231362}{0.499\times 10^{-3}}=1788.0006285\ bumps

The rate which the bumps hit the stylus = 33\times\dfrac{1788.0006285}{60}=983.400345675

The rate at which the bumps hit the stylus 983.400345675 hits per second

8 0
3 years ago
which type of relationship exists when a certain type of trees roots need a fungus present in order to grow normally
Afina-wow [57]
Judging on the fact that this is middle school physics, I would say that it is a beneficial relationship. 
5 0
4 years ago
Read 2 more answers
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