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3 years ago

What is the cause of change in properties of matter

Physics

1 answer:

Nikitich [7]3 years ago

3 0

Answer:

Chemical changes cause a substance to change into an entirely substance with a new chemical formula.

Explanation:

Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the end results are called products.

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A solar system has the five planets shown below. The mass of each planet is proportion

slava [35]

Answer:

Planet C

Explanation:

The figure of the problem is missing: find it in attachment.

The magnitude of the gravitational force between two objects is given by the equation:

$F=\frac{Gm_1 m_2}{r^2}$

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

In this problem, we have four planets around planet X, and the mass of each planet is proportional to its size in the figure.

As we can see from the previous equation, the magnitude of the gravitational force is proportional to the mass of the planets: therefore, the planet with largest mass will exert the largest gravitational force on planet X.

From the figure, we see that planet C has the largest size, so the largest mass: therefore, planet C exerts the greatest gravitational force on planet X.

6 0

4 years ago

a baseball is hit straight up into the air. If the initial velocity was 20 m/s, how high will the ball go?How long will it be un

AleksAgata [21]

1) The motion of the ball is an uniformly accelerated motion, with constant acceleration equal to $g=-10 m/s^2$ (the negative sign means it is directed towards the ground).

For an uniformly accelerated motion, we can use the following relationship:
$2gh=v_f^2-v_i^2$
where h is the maximum height reached by the ball, $v_i = 20 m/s$ is its initial velocity and $v_f$ the velocity of the ball when it reaches the maximum height. But $v_f=0$ (when the ball reaches the maximum height, it stops before going down, so its velocity at that moment is zero), so we can use the relationship to calculate h, the maximum height:
$h=- \frac{v_i^2}{2g} =- \frac{20 m/s)^2}{2 \cdot (-10 m/s^2)} =20 m$

2) We can find the time the ball takes to return to the ground by requiring that the space covered by the ball returns to zero:
$S(t)=0$
where for an uniformly accelerated motion,
$S(t)=v_i t + \frac{1}{2} gt^2 =0$
By solving this, we have two solutions: one is t=0, which corresponds to the moment the player hits the ball, the second one is
$t=- \frac{2 v_i}{g}=- \frac{2 \cdot 20 m/s}{-10 m/s^2}=4 s$
so, the ball returns to the ground after 4 s.

3) The velocity of the ball when it returns to the ground is given by:
$v(t) = v_i +gt=20 m/s + (-10 m/s^2)(4 s)=-20 m/s$
where the negative sign means the ball is going downwards.

8 0

3 years ago

How does a blue object look under all colors of light

OverLord2011 [107]

The "blue" object would look the same. Say that this blue object is a square. That "square" is every color but blue. The only reason that you see it as "blue" is because what we call "blue", it the only color of light that bounces back at our eyes. Under all colors of light, especially simultaneously. This square or any shape for that matter would absorb the other colors of light, but the blue will be rejected. Therefore, we can only see what bounces back at our eyes, which is the color blue in this case.

Hope this helps, WyattMarine501

6 0

3 years ago

Which equations could be used as is, or rearranged to calculate for frequency of a wave? Check all that apply.

amm1812

-- Equations #2 and #6 are both the same equation,
and are both correct.

-- If you divide each side by 'wavelength', you get Equation #4,
which is also correct.

-- If you divide each side by 'frequency', you get Equation #3,
which is also correct.
With some work, you can rearrange this one and use it to calculate
frequency.

Summary:

-- Equations #2, #3, #4, and #6 are all correct statements,
and can be used to find frequency.

-- Equations #1 and #5 are incorrect statements.

7 0

3 years ago

Read 2 more answers

Calculate the force of gravity on the 0.50-kg mass if it were 6.4×106 m above earth's surface (that is, if it were two earth rad

Sunny_sXe [5.5K]

Radius of Earth is given as

$R = 6.4 * 10^6 m$