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kipiarov [429]
3 years ago
7

Can someone answer these questions for me? It's for my study guide. I will be posting more questions soon.

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0
The first is 6.1 using the distance formula.
distance = sqrt((x2-x1)^2+(y2-y1)^2)
plug it all in and simplify
you get 6.1

the next one is the midpoint. u just take add both values of x together and divide by 2 to get the x coordinate and then add together both values of y and divide by 2 to get the y value. the midpoint is (8,7)

to find the perimeter of the rectangle, add the lengths of each side. 25 for the height and you would add 2 of those and then there are 2 sides as long as the length that you would add. it would be height+height+length+length which is 25+25+77+77=204. remember units so 204 ft
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Rudiy27

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3 years ago
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Is 4/10 more, less or equal to half​
zubka84 [21]

Answer:

less

Step-by-step explanation:

5/10 is equal to one half, but 4/10 is less than one half

7 0
3 years ago
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Find the equation of the line<br><br> Y= __x + __
djyliett [7]

Answer:

y=2x+5

Step-by-step explanation:

0,5

0,7

7-5 is 2

2/0 is 2

to check answer:

(2*0)+5

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8 0
3 years ago
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Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).
bija089 [108]

<em>Note: Since you missed to mention the the expression of the function </em>p(x)<em> . After a little research, I was able to find the complete question. So, I am assuming the expression as </em>p(x)=x^4-9x^2-4x+12<em> and will solve the question based on this assumption expression of  </em>p(x)<em>, which anyways would solve your query.</em>

Answer:

As

p\left(-2\right)=0

Therefore, x=-2 is a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12

As

p\left(2\right)=-16

Therefore, x=2 is not a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12

Step-by-step explanation:

As we know that for any polynomial let say<em> </em>p(x)<em>, </em>c is the root of the polynomial if p(c)=0.

In order to find which of the given values will be a root of the polynomial, p(x)=x^4-9x^2-4x+12<em>, </em>we must have to evaluate <em> </em>p(x)<em> </em>for each of these values to determine if the output of the function gets zero.

So,

Solving for p\left(-2\right)

<em> </em>p(x)=x^4-9x^2-4x+12

p\left(-2\right)=\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12

\mathrm{Simplify\:}\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12:\quad 0

\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12

\mathrm{Apply\:rule}\:-\left(-a\right)=a

=\left(-2\right)^4-9\left(-2\right)^2+4\cdot \:2+12

\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}

=2^4-2^2\cdot \:9+8+12

=2^4+20-2^2\cdot \:9

=16+20-36

=0

Thus,

p\left(-2\right)=0

Therefore, x=-2 is a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12<em>.</em>

Now, solving for p\left(2\right)

<em> </em>p(x)=x^4-9x^2-4x+12

p\left(2\right)=\left(2\right)^4-9\left(2\right)^2-4\left(2\right)+12

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

p\left(2\right)=2^4-9\cdot \:2^2-4\cdot \:2+12

p\left(2\right)=2^4-2^2\cdot \:9-8+12

p\left(2\right)=2^4+4-2^2\cdot \:9

p\left(2\right)=16+4-36

p\left(2\right)=-16

Thus,

p\left(2\right)=-16

Therefore, x=2 is not a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12<em>.</em>

Keywords: polynomial, root

Learn more about polynomial and root from brainly.com/question/8777476

#learnwithBrainly

7 0
3 years ago
Read 2 more answers
( 3u + 7 )( 5 - u )= 0​
mixas84 [53]

Answer:

The answer is 484. Please let me know if it helped you.

Step-by-step explanation:

5 0
3 years ago
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