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kumpel [21]
2 years ago
5

HURRY!! select ALL the correct answers

Mathematics
1 answer:
Rainbow [258]2 years ago
8 0

Answer:

2nd, 3rd and 5th options are correct.

Step by step explanation:

We are asked to find which of the given operations involving complex numbers have solutions represented by point A on the graph.

We can see that point A lies on (1,-2i). Let us see which of our given expressions give us coordinates of point A.

1. (4+i)+3(1+i)

4+i+3+3i

4+3+i+3i

7+4i

We can see that our 1st option is incorrect.

2. (4+i)-3(1+i)

4+i-3-3i

4-3-3i+i

1-2i

We can see that our 2nd option is correct.

3.  (4+i)+(-3-3i)

4+i-3-3i

4-3+i-3i

1-2i

We can see that our 3rd option is correct.

4.  (4+i)+(3-3i)

4+i+3-3i

4+3+i-3i

7-2i

Upon simplifying our expression we got 7-2i which is not equal to coordinates of point A. Therefore, 4th option is incorrect.

5. (4+i)-(3+3i)

4+i-3-3i

4-3+i-3i

1-2i

Upon simplifying our expression we got coordinates of point A. Therefore, 5th option is correct indeed.



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What is the solution of the system? Use elimination.
sweet [91]

Answer:

The solutions to the system of the equations by the elimination method will be:

x=2,\:z=-1,\:y=2

Step-by-step explanation:

Given the system of the equations

2x\:+\:2y\:+z\:=\:7

-x-\:y\:+z\:=\:-5

x+3y-4z=12

solving the system of the equations by the elimination method

\begin{bmatrix}2x+2y+z=7\\ -x-y+z=-5\\ x+3y-4z=12\end{bmatrix}

\mathrm{Multiply\:}-x-y+z=-5\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y+2z=-10

\begin{bmatrix}2x+2y+z=7\\ -2x-2y+2z=-10\\ x+3y-4z=12\end{bmatrix}

-2x-2y+2z=-10

+

\underline{2x+2y+z=7}

3z=-3

\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ x+3y-4z=12\end{bmatrix}

2x+6y-8z=24

-

\underline{2x+2y+z=7}

4y-9z=17

\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ 4y-9z=17\end{bmatrix}

Rearranging the equations

\begin{bmatrix}2x+2y+z=7\\ 4y-9z=17\\ 3z=-3\end{bmatrix}

solve 3z=-3 for z:

z=-1

\mathrm{For\:}4y-9z=17\mathrm{\:plug\:in\:}z=-1

solve  4y-9\left(-1\right)=17 for y:

4y-9\left(-1\right)=17

4y+9=17

4y=8

y=2

\mathrm{For\:}2x+2y+z=7\mathrm{\:plug\:in\:}z=-1,\:y=2

solve 2x+2\cdot \:2-1=7 for x:

2x+2\cdot \:2-1=7

2x+3=7

2x=4

x=2

Therefore, the solutions to the system of the equations by the elimination method will be:

x=2,\:z=-1,\:y=2

5 0
2 years ago
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Answer:

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Eddi Din [679]

Answer:

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Step-by-step explanation:

Area of a rectangle formula:

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Work:

A = bh

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A = \frac{15}{4}

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The answer to the question is c 
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