$\left(\frac{(x^4y^{-2})^4}{(2x^2)^2\cdot2x^0y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{4x^4\cdot2y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{8x^4y^3}\right)^2=\\
\left(\frac{x^{12}y^{-11}}{8}\right)^2=\\
\frac{x^{24}y^{-22}}{64}$

3 0

3 years ago

What is the square and cube of 12?

Inessa [10]

Hello!!

Square of 12: $12^2$ or 12 * 12 = 144

Cube of 12: $12^3$ or 12 * 12 * 12 = 1728

Good luck :)

6 0

3 years ago

1/2 x -41 <br> x=10<br><br> Simplify the answer

Darya [45]

If I'm interpreting this right, it's -36 since a half times ten is 5... so it comes down to 5-41 which equals -36.

6 0

2 years ago