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Mrac [35]
3 years ago
14

2/3 of the women at the party wear jewelry. 1/4 of the women wear a black dress. If there are 50 more women wearing jewelry than

women with a black dress and half the women wearing a black dress also wear jewelry then how many women are there at the party?
please explain how to set up the equation to solve

i need to know for an important exam
Mathematics
1 answer:
Alinara [238K]3 years ago
3 0

To solve this question, let's start by writing down what we know. First of all, let's make a variable, x, which will stand for the number of women at the party (because that's what we want to find). Using this variable, we know:

2/3x have jewelry

1/4x have a black dress

Half the people wearing a black dress also have jewelry, so we know that there is an overlap of 1/4x ÷ 2 = 1/8x between the jewelry and black dress.

To account for this overlap, we can subtract it from both sides. We get

2/3x - 1/8x = 13/24x

1/4x - 1/8x = 1/8x

We know that there are 50 more women with a black dress, so:

13/24x = 1/8x + 50

Simplifying, we get:

13/24x = 3/24x + 50

10/24x = 50

x = 50*24/10 = 120

That means that there were 120 women at the party.

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Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

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The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

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Read 2 more answers
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

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3 years ago
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Answer: odd

Step-by-step explanation:

Given

The graph of a function increases as x increases and decreases as x decreases.

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