The half-life of polonium-210, given that it decays from 98.3 micrograms to 12.3 micrograms in 414 days is 138 days
<h3>How to determine the number of half-lives </h3>
- Original amount (N₀) = 98.3 micrograms
- Amount remaining (N) = 12.3 micrograms
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = 98.3 / 12.3
2ⁿ = 8
2ⁿ = 2³
n = 3
<h3>How to determine the half life </h3>
- Number of half-lives (n) = 3
- Time (t) = 414 days
- Half-life (t½) = ?
t½ = t / n
t½ = 414 / 3
t½ = 138 days
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Answer:
4x^3
Explanation:
Solubility product constant is usually written as (Ksp). It is defined for equilibrium between a solids and its respective ions in a solution. Its value indicates the degree to which a compound dissociates into ions in water. The higher the solubility product constant, the more soluble the compound.
Solubility of a solute is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium while the solubility product constant (Ksp) describes the equilibrium between a solid and its constituent ions in a solution.
For AB2(s)< -------> A(aq) + 2B(aq). But solubility of AB2= x
Ksp= x × (2x)^2
Ksp= 4x^3
It is approximately 10 ^ -10
Im going for d i think i took this last year
It’s chlorine (Cl) having the atomic number 17
