Explanation:
First, let's review the ideal gas law, PV = nRT. In this equation, 'P' is the pressure in atmospheres, 'V' is the volume in liters, 'n' is the number of particles in moles, 'T' is the temperature in Kelvin and 'R' is the ideal gas constant (0.0821 liter atmospheres per moles Kelvin).
The anwer is 10,000 fahrenheit
Answer:
Ka = 1.5 × 10⁻⁵
Explanation:
Butyric acid is a weak acid that ionizes according to the following equation:
CH₃-CH₂-CH₂-COOH(aq) ⇄ CH₃-CH₂-CH₂-COO⁻(aq) + H⁺(aq)
We can find the value of the acid dissociation constant (Ka) using the following expression:
![Ka=\frac{[H^{+}]^{2} }{Ca}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%20%7D%7BCa%7D)
where
[H⁺] is the molar concentration of H⁺
Ca is the initial molar concentration of the acid
We can find [H⁺] from the pH.
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -2.71 = 1.95 × 10⁻³ M
Then,
The decrease in the freezing point of the solution is −1.86oC.
<h3>What is the decrease in the freezing point?</h3>
Now we know that the freezing point depression of a solid is a colligative property of the solution.
Thus we have that;
ΔT = K m i
ΔT = freezing point depression
K = freezing constant
m = molality of the solution
i = Van't Hoff factor
Thus;
molality = 1 mol/1 Kg = 1 m
ΔT = −1.86oC/m * 1 m * 1
ΔT =−1.86oC
Learn more about freezing point:brainly.com/question/3121416
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Answer:
0.015 M HNO3 = 0.015 M H3O+ pH = -log(0.015) = 1.82 [OH -] = 1.0 x 10 -14/0.015 M = 6.7 x 10 13 Check: HNO3 is a strong acid, so we expect the pH to be low and the [OH ] to be small
