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4 years ago

Which is least likely to cause eutrophication?

Chemistry

2 answers:

dangina [55]4 years ago

3 0

The answer is nitrates.

cupoosta [38]4 years ago

3 0

The answer is: pesticides.

Eutrophication is a process by which nutrients, particularly phosphorus and nitrogen, become highly concentrated in a water, leading to increased growth of algae or cyanobacteria.

Fertilizers contain phosphorus and nitrogen, pesticide do not.

NPK ratio system is a conventional shorthand for the ratio of the nitrogen (N), phosphorus (P) and potassium (K) in a fertilizer.

Eutrophication is a serious environmental problem.

You might be interested in

Which compound does H2SO4 represent when in an aqueous solution?

solong [7]

H₂SO₄ represents Sulphuric acid or SO₄²⁻ ion when in aqueous as well as H⁺ and a little amount of HSO₄⁻ all of these ions can form in aqueous on dissolving H₂SO₄

4 0

3 years ago

Read 2 more answers

1. Write the balanced chemical reaction for silver metal reacting with phosphoric acid to form

Anon25 [30]

<h3>Answer:</h3>

75.51%

<h3>Solution and Explanation:</h3>

Balanced equation: 6Ag(s) + 2H₃PO₄(aq) → 2Ag₃PO₄(aq) + 3H₂(g)

To determine the percent yield of silver phosphate we will use the following steps;

Step 1: Determine the number of moles of Silver metal used

Mass of silver metal = 50.00 grams

Molar mass of silver is 107.87 g/mol

Therefore;

Moles of silver = 50.0 g ÷ 107.87 g/mol

= 0.464 moles

Step 2: Determine moles of silver phosphate produced

From the equation, 6 moles of Ag reacts with 2 moles of phosphoric acid to yield 2 moles of silver phosphate.

Thus, the mole ratio of silver metal to silver phosphate is 6 : 2

Therefore;

Moles of Ag₃PO₄ = Moles of Ag × 2/6

= 0.464 moles × 2/6

= 0.155 moles

Step 3: Calculate the theoretical mass of silver phosphate produced

Mass = Number of moles × Molar mass

Number of moles of Ag₃PO₄= 0.155 moles

Molar mass of Ag₃PO₄ =418.58 g/mol

Therefore;

Theoretical mass of Ag₃PO₄ = 0.155 moles × 418.58 g/mol

= 64.88 g

Step 4: Calculate the percent yield of Ag₃PO₄

$percent yield=\frac{Actual mass}{Theoretical mass}(100)$

Actual mass of Ag₃PO₄ = 48.99 g

Theoretical mass of Ag₃PO₄ = 64.88 g

Therefore;

% yield of Ag₃PO₄ = (48.99 g ÷ 64.88 g)×100%

= 75.51%

Hence, the percent yield of Ag₃PO₄ is 75.51%

6 0

4 years ago

Which volume is the greatest?

Zolol [24]

centiliter is the correct answer

7 0

3 years ago

the rate constant for the decomposition of acetaldehyde, ch3cho, to methane, ch4, and carbon monoxide, co, in the gas phase is 1

Mademuasel [1]

The rate constant for the decomposition of acetaldehyde, CH₃CHO, to methane, CH₄, and carbon monoxide, CO, in the gas phase is 1.10 × 10² m⁻¹ s⁻¹ at 703.7 k and 4.90 x 10⁻² m⁻¹ s⁻¹ at 865 k.The activation energy for this decomposition in KJ/mole is 154.303

To determine the activation energy of a reaction (Ea) from two reaction rates (k₁ and k₂) at two different temperatures (T₁ and T₂).

we use the equation -

k₂ = Eₐ x ( 1 - 1 )

k₁ R T₁ T₂

Where,

R is the gas constant (8.3145 J/mol.K).

We have -

k₁= 1.10 x 10⁻² m⁻¹ s⁻¹

T₁= 703.7 K

k₂= 4.90 x 10⁻² m⁻¹ s⁻¹

T₂= 865 K

Putting the values in the equation -

4.90 x 10⁻² m⁻¹ s¹ = Ea x ( 1 - 1 )

1.10 x 10⁻² m⁻¹ s⁻¹ (8.3145 J/K.mol) 703.7 K 865 K

Ea = (4.90 x 10⁻² m⁻¹ s⁻¹) / ( 1 - 1 ) x (8.3145 J/K.mol)

1.10 x 10⁻² m⁻¹ s⁻¹ 703.7 K 851 K

Ea = 154303 J/mol

When divided by 1000,

Ea in KJ/mol = 154.303 KJ/mol

To learn more about activation energy,

brainly.com/question/8911926

#SPJ4

3 0

1 year ago

What is 9.6 times 10 to 7th power divided by 3.0 times 10 to the 5th power?

Juli2301 [7.4K]

Answer:

9.6 times 10 to 7th power divided by 3.0 times 10 to the 5th power can be written as follow. The final answer is 320.

Explanation:

When the divide 9.6 by 3.0 we get 3.2 and

$\frac{10^{a}}{10^{b}}=10^{(a-b)}$

So the calculation is as below.

$\frac{9.6\times 10^{7}}{3.0\toimes 10^{5}}=3.2\times 10^{(7-5)}\\\frac{9.6\times 10^{7}}{3.0\toimes 10^{5}}=3.2\times 10^{2}\\\frac{9.6\times 10^{7}}{3.0\toimes 10^{5}}=3.2\times 100\\\\ \frac{9.6\times 10^{7}}{3.0\toimes 10^{5}}=320$

7 0

3 years ago