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2 years ago

1, 2, or 3...help please

Chemistry

2 answers:

Mashcka [7]2 years ago

7 0

Answer:

molecular so number 3. ...

e-lub [12.9K]2 years ago

4 0

Number 3 I hope this helps

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5.40 g B determine the number of atoms

sdas [7]

Atomic mass Boron ( B ) = 10.811 u.m.a

10.811 g -------------- 6.02x10²³ atoms
5.40 g ----------------- ?? atoms

5.40 x ( 6.02x10²³) / 10.811 =

3.0069x10²³ atoms

4 0

3 years ago

A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o

statuscvo [17]

Answer: The value of $K_{eq}$ is 0.044

Explanation:

We are given:

Initial moles of methane = $4.10\times 10^{-2}mol=0.0410moles$

Initial moles of carbon tetrachloride = $6.51\times 10^{-2}mol=0.0651moles$

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

$\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}$

So, concentration of methane = $\frac{0.0410}{1.00}=0.0410M$

Concentration of carbon tetrachloride = $\frac{0.0651}{1.00}=0.0651M$

The given chemical equation follows:

$CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)$

Initial: 0.0410 0.0651

At eqllm: 0.0410-x 0.0651-x 2x

We are given:

Equilibrium concentration of carbon tetrachloride = $6.02\times 10^{-2}M=0.0602M$

Evaluating the value of 'x', we get:

$\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M$

Now, equilibrium concentration of methane = $0.0410-x=[0.0410-0.0049]=0.0361M$

Equilibrium concentration of $CH_2Cl_2=2x=[2\times 0.0049]=0.0098M$

The expression of $K_{eq}$ for the above reaction follows:

$K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}$

Putting values in above expression, we get:

$K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044$

Hence, the value of $K_{eq}$ is 0.044

8 0

3 years ago

In Europe, gasoline efficiency is measured in km/L. If your car’s gas mileage is 25.0 mi/gal, how many liters of gasoline would

Deffense [45]

Answer:

$V=23.5L$

Explanation:

Hello,

In this case, it is convenient to compute the car's mileage in km/L as follows:

$25.0\frac{mi}{gal}*\frac{1km}{0.6214mi}*\frac{1gal}{3.78L}=10.64\frac{km}{L}$

In such a way, since the distance is measured to be 250 km, the volume requirement is:

$V=\frac{250km}{10.64kg/L}\\ \\V=23.5L$

Regards.

7 0

3 years ago

A perfect cube of aluminum metal was found to weigh 20.00 g. The density of aluminum is 2.7 g/ml. What are the dimensions of the

denis23 [38]

Answer:

Height = 1.9493 cm

Width = 1.9493 cm

Depth = 1.9493 cm

Solution:

Data Given:

Mass = 20 g

Density = 2.7 g/mL

Step 1: Calculate the Volume,

As,

Density = Mass ÷ Volume

Or,

Volume = Mass ÷ Density

Putting values,

Volume = 20 g ÷ 2.7 g/mL

Volume = 7.407 mL or 7.407 cm³

Step 2: Calculate Dimensions of the Cube:

As we know,

Volume = length × width × depth

So, we will take the cube root of 7.407 cm³ which is 1.9493 cm.

Hence,

Volume = 1.9493 cm × 1.9493 cm × 1.9493 cm

Volume = 7.407 cm³

4 0

3 years ago

1. In regards to curly hair, which of the following statements

Kamila [148]

Answer:

A and D are the answers

Explanation:

the other two don't make sense

3 0

2 years ago