Answer : The mass of
required is 9.3092 grams.
Explanation :
First we have to calculate the mass of solution.
![\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20solution%7D%3D%5Ctext%7BDensity%20of%20solution%7D%5Ctimes%20%5Ctext%7BVolume%20of%20solution%7D)
![\text{Mass of solution}=1.065g/mL\times 25.0mL=26.625g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20solution%7D%3D1.065g%2FmL%5Ctimes%2025.0mL%3D26.625g)
Now we have to calculate the mass of acetic acid.
As we are given that the 58.0 % acetic acid by mass. That means, 58.0 grams of acetic acid present in 100 grams of solution.
As, 100 g of solution contains 58.0 g of acetic acid
So, 26.625 g of solution contains
of acetic acid
Now we have to calculate the moles of acetic acid.
Molar mass of acetic acid = 60 g/mole
![\text{Moles of }CH_3COOH=\frac{\text{Mass of }CH_3COOH}{\text{Molar mass of }CH_3COOH}=\frac{15.44g}{60g/mole}=0.257moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DCH_3COOH%3D%5Cfrac%7B%5Ctext%7BMass%20of%20%7DCH_3COOH%7D%7B%5Ctext%7BMolar%20mass%20of%20%7DCH_3COOH%7D%3D%5Cfrac%7B15.44g%7D%7B60g%2Fmole%7D%3D0.257moles)
Now we have to calculate the moles of
.
The balanced chemical reaction is,
![2CH3CO_2H+Ca(OH)_2\rightarrow Ca(CH_3CO_2)_2+2H_2O](https://tex.z-dn.net/?f=2CH3CO_2H%2BCa%28OH%29_2%5Crightarrow%20Ca%28CH_3CO_2%29_2%2B2H_2O)
From the balanced reaction we conclude that,
As, 2 moles of
react with 1 moles of ![Ca(OH)_2](https://tex.z-dn.net/?f=Ca%28OH%29_2)
So, 0.257 moles of
react with
moles of ![Ca(OH)_2](https://tex.z-dn.net/?f=Ca%28OH%29_2)
Now we have to calculate the mass of
.
![\text{Mass of }Ca(OH)_2=\text{Moles of }Ca(OH)_2\times \text{Molar mass of }Ca(OH)_2](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DCa%28OH%29_2%3D%5Ctext%7BMoles%20of%20%7DCa%28OH%29_2%5Ctimes%20%5Ctext%7BMolar%20mass%20of%20%7DCa%28OH%29_2)
Molar mass of
= 74 g/mole
![\text{Mass of }Ca(OH)_2=(0.1258mole)\times (74g/mole)=9.3092g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DCa%28OH%29_2%3D%280.1258mole%29%5Ctimes%20%2874g%2Fmole%29%3D9.3092g)
Therefore, the mass of
required is 9.3092 grams.