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Kipish [7]
3 years ago
8

a rectangle is inscribed in a circle of radius r. if the rectangle has length 3x, write the area of the rectangle as the product

of two function in terms of x and r
Mathematics
1 answer:
svetlana [45]3 years ago
5 0
Based on the given condition, since the rectangle is inscribed in a circle given the length to be 3x, the width can be approximated by taking the right triangle formed by the radius and the w/2, sin 45 = w/2/r, which is equal to w = 2r sin45, therefore the Area of the inscribed rectangle = LxW = (3x)(2rsin45)
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4(960+2-125)+5 what is the solution to this mathematical expression?
seropon [69]

Answer:

3353

Step-by-step explanation:

1. Simplify 960 + 2 to 962.

4 · (962 − 125) + 5

2. Simplify 962 − 125 to 837.

4 · 837 + 5

3. Simplify 4 · 837 to 3348.

3348 + 5

4. Simplify

3353

5 0
4 years ago
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Answer:

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Step-by-step explanation:

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D(A-B)=C

Flip the equation

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7 0
3 years ago
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stiks02 [169]
5 times sign 2+7=17 you have to times 5 and 2 and when u get the answer add it with seven
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3 years ago
Help me solve this problem in the photo, need help asap
Rudik [331]
\dfrac{2x^2+7x-4}{2x^2-32}=\\
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slava [35]

1st number=7 and 2nd number =11

Step-by-step explanation:

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7 0
3 years ago
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