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3 years ago

What is the unit rate $140 for 18ft

Mathematics

1 answer:

scZoUnD [109]3 years ago

8 0

You have an equation:18ft=$140. To find the unit rate for ft, divide both by 18:/18ft= $140/18= $7.78/1ft.

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What is 38 in denary in base 8

Naily [24]

First divide by 8:_

38 / 8 = 4 remainder 6

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3 years ago

What is the solution to x-3>4

weeeeeb [17]

$\bold{Answer}$

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3 years ago

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The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for hou

o-na [289]

This question s incomplete, the complete question is;

The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.

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Answer:

The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr

Step-by-step explanation:

Given the data in the question;

let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively

x + y = 55 ----------------equ1

x = 55 - y ------------------qu2

also

15x + 30y = 1050

x + 2y = 70 --------------equ3

input equ2 into equ3

(55 - y) + 2y = 70

- y + 2y = 70 - 55

y = 15

input value of y into equ1

x + 15 = 55

x = 55 - 15

x = 40

Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr

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3 years ago

The sale price of an item is $180 after a 25% discount is applied. What is the original price of the item?

torisob [31]

original price is $240

5 0

3 years ago

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The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

Let X = number of hours spent per week on household chores

So, assuming data follows normal distribution; X ~ N( $\mu=28,\sigma^{2}=7^{2}$ )

The z score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean hours = 28

$\sigma$ = standard deviation = 7 hours

n = sample of adults = 49

Let $\bar X$ = sample mean hours spent per week on household chores

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P( $\bar X$ > 26.75 hours)

P( $\bar X$ > 26.75 hours) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{26.75-28}{\frac{7}{\sqrt{49} } }$ ) = P(Z > -1.25) = P(Z < 1.25)

= 0.89435 {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

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3 years ago

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