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ella [17]
4 years ago
15

For which of these is there an increase in entropy? KCI(aq)+AgNO3(aq)KNO3(aq)+AgCI(s) NaCl(s)NaCl(aq) 2NaOH(aq)+CO2(g)Na2CO3(aq)

+H20(1) C2H5OH(g)C2H5OH(I)
Chemistry
1 answer:
vovikov84 [41]4 years ago
5 0

Answer: NaCl (s) → NaCl (aq)

Explanation:

Entropy is often associated with the disorder or randomness of a system. Therefore, in each reaction, it is necessary to evaluate if the disorder increases or decreases to understand what happens to the entropy:

1) KCl (aq) + AgNO₃ (aq) → KNO₃ (aq) + AgCl (s) - In this reaction, we have only aqueous reactants in the beginning and in the product we have a precipitate. The solid state is more organised than the liquid, consequently, the entropy decreases.

2) NaCl (s) → NaCl (aq) - In this case, oposite to the first one, we go from a solid state to an aqueous state. The solvation of the ions Na⁺ and Cl⁻ is random while the solid state is very organised. Therefore, in this reaction the entropy increases.

3) 2NaOH (aq) + CO₂ (g) → Na₂CO₃ (aq) + H₂O (l) - In this reaction, the reactants have higher entropy because of the gas CO₂. Therefore, the entropy decreases.

4) C₂H₅OH (g) → C₂H₅OH (l) -  In this reaction, the reactant is a gas and the product a liquid. Therefore, the entropy decreases.

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Alex787 [66]

Answer:

At the plate boundary, there would be a divergent boundary where we can see a mid ocean ridge and a gap. We would be able to see the mantle because there would be a fissure from where magma will rise and solidify.    

Explanation:

Under the South American plate and African plate, there are currents that cause a divergent boundary. They create this boundary since they pull the tectonic plates apart, causing a mid-ocean ridge with an opening that allows the rising of the magma that was underneath. Once that the magma is out, it solidifies, and the currents will try to create another ridge to repeat the process.

When the plates are apart, the mantle that is beneath is exposed, and we can see the magma.

4 0
3 years ago
b) 2C2H2(g) + 5O2(g)⟶4CO2(g) + 2H2O(l) 6.54 Calculate the heats of combustion for the following reactions from the standard enth
IRINA_888 [86]

Answer:

a.  ΔH⁸ =  -1420 kJ/mol       b. ΔH⁸ =  -1144.84 kJ/mol

Explanation:

a.

                 C₂H₄ (g) + 3 O₂ (g) ------------------------  4 CO₂ (g) + 2 H₂O (l)  ΔH⁸ = ?

ΔH⁸f  kJmol  52.47       0                                      -399.5            -285.83

ΔH⁸ = 2(-399.5) + 2 (-285.83) - (52.47)

ΔH⁸ =  -1420 kJ/mol

b.

                       H₂S (g) + 3 O₂ (g) ---------------------- 2 H₂O (l)  + 2 SO₂ (g)

ΔH⁸f  kJmol     -20.50     0                                    -285.83      -296.84

ΔH⁸ =  2(-285.83) + 2 (-296.84) - (-20.50)

ΔH⁸ =  -1144.84 kJ/mol

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3 years ago
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7 0
3 years ago
A gas is produced when 25 g of substance X is mixed into 60 g of solution Z in a beaker. The mass of the solution in the beaker
Zepler [3.9K]

mass of the gas = 10 g

<h3>Further explanation</h3>

<em>The law of conservation of mass :</em>

<em>In a closed / isolated system, the total mass of the substance before the reaction will be equal to the total mass of the reaction product.</em>

Reaction

\tt X+Z\rightarrow gas+solution

mass before reaction=mass after reaction

\tt 25+60=gas+75\\\\gas=25+60-75=10~g

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