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ella [17]
3 years ago
15

For which of these is there an increase in entropy? KCI(aq)+AgNO3(aq)KNO3(aq)+AgCI(s) NaCl(s)NaCl(aq) 2NaOH(aq)+CO2(g)Na2CO3(aq)

+H20(1) C2H5OH(g)C2H5OH(I)
Chemistry
1 answer:
vovikov84 [41]3 years ago
5 0

Answer: NaCl (s) → NaCl (aq)

Explanation:

Entropy is often associated with the disorder or randomness of a system. Therefore, in each reaction, it is necessary to evaluate if the disorder increases or decreases to understand what happens to the entropy:

1) KCl (aq) + AgNO₃ (aq) → KNO₃ (aq) + AgCl (s) - In this reaction, we have only aqueous reactants in the beginning and in the product we have a precipitate. The solid state is more organised than the liquid, consequently, the entropy decreases.

2) NaCl (s) → NaCl (aq) - In this case, oposite to the first one, we go from a solid state to an aqueous state. The solvation of the ions Na⁺ and Cl⁻ is random while the solid state is very organised. Therefore, in this reaction the entropy increases.

3) 2NaOH (aq) + CO₂ (g) → Na₂CO₃ (aq) + H₂O (l) - In this reaction, the reactants have higher entropy because of the gas CO₂. Therefore, the entropy decreases.

4) C₂H₅OH (g) → C₂H₅OH (l) -  In this reaction, the reactant is a gas and the product a liquid. Therefore, the entropy decreases.

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What is the highest energy to which doubly ionized helium atoms (alpha particles) can be accelerated in a DC accelerator with 3
pentagon [3]

Answer:

Highest energy will be equal to 9.6\times 10^{-13}J

Explanation:

Charged on doubly ionized helium atom q=2e=2\times 1.6\times 10^{-19}C=3.2\times 10^{-19}C

It is accelerated with maximum voltage of 3 MV

So voltage V=3\times 10^6volt

Now energy is given by E=qV=3.2\times 10^{-19}\times 3\times 10^6=9.6\times 10^{-13}J

So highest energy will be equal to 9.6\times 10^{-13}J

5 0
3 years ago
O, li, c which electrons experience the greatest effective nuclear charge? express your answer as a chemical formula.
Nataly_w [17]
<span>The effective nuclear charge of an atom = total electrons - inner electrons For O, ENC = 8 - 2 = 6 For Li, ENC = 3 - 2 = 1 For C, ENC = 6 - 2 = 4 The electrons in O experience the greatest effective nuclear charge and that is why O is smaller than C (which is smaller than Li).</span>
5 0
3 years ago
1‑propanol ( n ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure a
Alex777 [14]

Answer:

y_{prop} = 0.134; y_{iso} = 0.866

The partial pressure of isopropanol = 34.04 Torr; The partial pressure of propanol = 5.26 Torr

Explanation:

For each of the solutions:

mole fraction of isopropanol  (x_{iso}) = 1 - mole fraction of propanol (x_{prop}).

Given: mole fraction of propanol = 0.247. Thus, the mole fraction of isopropanol = 1 - 0.247 = 0.753.

Furthermole, the partial pressure of isopropanol = x_{iso}*vapor pressure of isopropanol = 0.753*45.2 Torr = 34.04 Torr

The partial pressure of propanol = x_{prop}*vapor pressure of propanol = 0.247*20.9 Torr = 5.16 Torr

Similarly,

In the vapor phase,

The mole fraction of propanol (y_{prop}) = \frac{P_{prop} }{P_{prop}+P_{iso}}

Where, P_{prop} is the partial pressure of propanol and P_{iso} is the partial pressure of isopropanol.

Therefore,

y_{prop} = 5.26/(34.04+5.16) = 0.134

y_{iso} = 1 - 0.134 = 0.866

5 0
4 years ago
Ice Station Bravo near the North Pole launched a helium-filled balloon to check atmospheric conditions. At sea level (1.0 atm) w
Reika [66]

Answer:

12.9 m³ is the new volume

Explanation:

As the temperature keeps on constant, and the moles of the gas remains constant too, if we decrease the pressure, the volume will increase.  If the volume is decreased, pressure will be higher.

The relation is this: P₁ . V₁  = P₂  . V₂

1 atm . 0.93m³ = 0.072 atm . V₂

0.93m³ .atm / 0.072 atm = V₂

V₂ = 12.9 m³

In conclusion and as we said, pressure has highly decreased so volume has highly increased.

8 0
3 years ago
Can anybody plz answer
Lelechka [254]

Answer: heat

Other indicators: color change, odor, gas, temperature change.

3 0
3 years ago
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