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ella [17]
3 years ago
15

For which of these is there an increase in entropy? KCI(aq)+AgNO3(aq)KNO3(aq)+AgCI(s) NaCl(s)NaCl(aq) 2NaOH(aq)+CO2(g)Na2CO3(aq)

+H20(1) C2H5OH(g)C2H5OH(I)
Chemistry
1 answer:
vovikov84 [41]3 years ago
5 0

Answer: NaCl (s) → NaCl (aq)

Explanation:

Entropy is often associated with the disorder or randomness of a system. Therefore, in each reaction, it is necessary to evaluate if the disorder increases or decreases to understand what happens to the entropy:

1) KCl (aq) + AgNO₃ (aq) → KNO₃ (aq) + AgCl (s) - In this reaction, we have only aqueous reactants in the beginning and in the product we have a precipitate. The solid state is more organised than the liquid, consequently, the entropy decreases.

2) NaCl (s) → NaCl (aq) - In this case, oposite to the first one, we go from a solid state to an aqueous state. The solvation of the ions Na⁺ and Cl⁻ is random while the solid state is very organised. Therefore, in this reaction the entropy increases.

3) 2NaOH (aq) + CO₂ (g) → Na₂CO₃ (aq) + H₂O (l) - In this reaction, the reactants have higher entropy because of the gas CO₂. Therefore, the entropy decreases.

4) C₂H₅OH (g) → C₂H₅OH (l) -  In this reaction, the reactant is a gas and the product a liquid. Therefore, the entropy decreases.

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Green light has a wavelength of 550nm. What is the frequency of a photon of green light?
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Answer:- Frequency is 5.4*10^1^4Hz .

Solution:- frequency and wavelength are inversely proportional to each other and the equation used is:

\nu =\frac{c}{\lambda }

where, \nu is frequency, c is speed of light and \lambda is the wavelength.

Speed of light is 3.0*10^8m/s .

We need to convert the wavelength from nm to m.

( 1nm=10^-^9m )

550nm(\frac{10^-^9m}{1nm})

= 5.5*10^-^7m

Now, let's plug in the values in the equation to calculate the frequency:

\nu =\frac{3.0*10^8m.s^-^1}{5.5*10^-^7m}

= 5.4*10^1^4s^-^1 or 5.4*10^1^4Hz

since, 1s^-^1=1Hz

So, the frequency of the green light photon is 5.4*10^1^4Hz .

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2 years ago
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Explanation:

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