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3 years ago

Blood ph is kept near a value of 7.3 - 7.5 because of

Chemistry

2 answers:

Ede4ka [16]3 years ago

5 0

Answer: Neutral Value

Explanation: pH of the blood is maintained at 7.0 to 7.5that is neutral value.

This is because if the pH of the is lower than the maintained value then it will become acidic .

Acidic pH can cause the medical urgency known as acidosis leading to vomiting, diarrhea etc.

If the pH becomes higher, then the blood will become basic in nature and it can also leas to the death of the person.

That is why the pH of the blood is maintianed at neutral value of 7.0 to 7.5

vekshin13 years ago

5 0

Blood PH is kept near a value of 7.3 - 7.5 because of buffers.

Many of the cells in the body can only function within a range near a neutral PH, some of the enzymes responsible for production and growth, and breaking down the food we consume and help in other important function within the human body works within a certain PH range.

<h2>Further Explanation</h2>

The buffers, which are present in almost the entire living solution helps to maintain this PH.

The blood is made up of large amount of carbonic acid, bicarbonate, a weak acid and a base. Together they assists in maintaining the blood level at 7.4. However, a higher or lower PH level can be very dangerous.

If the blood PH level is below 6.8 or above 7.8, individual can fall sick or even die. The presence of bicarbonate in the blood helps to neutralizes excess acid while carbonic acids help to neutralizes excess bases.

Any substance that minimizes or stops massive changes in PH is called a buffer. Every buffer has a particular buffer capacity and range. The buffer capacity is the amount of base or acid that is added to the PH level before it changes significantly while the buffer range refers to the PH range where a buffer neutralizes the acid and base that is added effectively.

LEARN MORE:

pH of our blood brainly.com/question/12855542

KEYWORDS:

buffers
ph level
acid
base
carbonic
enzymes

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2 years ago

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Explain why we use 1/12 in finding atomic mass unit ?

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Answer:

The u (amu is the old unit name) is 1/12 of the weight of an 12C atom. The way the u is chosen ensures that all core and atom masses are multiples of 1(±0.1) u.

Explanation:

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3 years ago

Mr. Jones, the science teacher, tells his students that energy cannot be created; it must be captured from the environment. He i

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The law of conservation of energy or first law of thermodynamics

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From the context we can infer that Mr. Jones was describing the law of conservation of energy.

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3 years ago

Calculate the maximum volume (in mL) of 0.143 M HCl that each of the following antacid formulations would be expected to neutral

Nuetrik [128]

Answer:

a. The maximum volume of 0.143 M HCl required is 154.4 mL.

b. The maximum volume of 0.143 M HCl required is 135.7 mL.

Explanation:

$Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O$

Mass of aluminum hydroxide = 350 mg = 0.350 g ( 1mg = 0.001 g)

Moles of aluminum hydroxide = $\frac{0.350 g}{78 g/mol}=0.004487 mol$

According to reaction ,3 moles of HCl neutralize 1 mole of aluminum hydroxide.Then 0.004487 mole of aluminum hydroxide will be neutralize by :

$\frac{3}{1}\times 0.004487 mol=0.01346 mol$ of HCl.

$Mg(OH)_2+2HCl\rightarrow MgCL_2+2H_2O$

Mass of magnesium hydroxide = 250 mg = 0.250 g ( 1mg = 0.001 g)

Moles of magnesium hydroxide = $\frac{0.250 g}{58 g/mol}=0.004310 mol$

According to reaction ,2 moles of HCl neutralize 1 mole of magnesium hydroxide.Then 0.004310 mole of magnesium hydroxide will be neutralize by :

$\frac{2}{1}\times 0.004310 mol=0.008621 mol$ of HCl.

Total moles of HCl required to neutralize both :

0.01346 mol + 0.008621 mol = 0.02208 mol

Molarity of the HCL solution = 0.143 M

Volume of the solution = V

$Molarity=\frac{\text{Total moles of HCl}{\text{Volume in Liter}}$

$V=\frac{0.02208 mol}{0.143 M}=0.1544 L$

1 L = 1000 mL

0.1544 L = 154.4 mL

The maximum volume of 0.143 M HCl required is 154.4 mL.

$CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2$

Mass of calcium carbonate = 970mg = 0.970 g ( 1mg = 0.001 g)

Moles of calcium carbonate = $\frac{0.970 g}{100 g/mol}=0.00970 mol$

According to reaction ,2 moles of HCl neutralize 1 mole of calcium carbonate.Then 0.00970 mole of calcium carbonate will be neutralize by :

$\frac{2}{1}\times 0.00970 mol=0.0194 mol$ of HCl.

Total moles of HCl required to neutralize calcium carbonate : 0.0194 mol

Molarity of the HCL solution = 0.143 M

Volume of the solution = V

$Molarity=\frac{\text{Total moles of HCl}}{\text{Volume in Liter}}$

$V=\frac{0.0194 mol}{0.143 M}=0.1357 L$

1 L = 1000 mL

0.1357 L = 135.7 mL

The maximum volume of 0.143 M HCl required is 135.7 mL.

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3 years ago

Determine the mass of Al(C2H3O2)3 that contains 2.63 Χ 1024 atoms of oxygen.

sergejj [24]

The molecular formula of compound is $Al(C_{2}H_{3}O_{2})_{3}$ .

Since, in 1 mole of $Al(C_{2}H_{3}O_{2})_{3}$ there are $6.023\times 10^{23}$ atoms of $Al(C_{2}H_{3}O_{2})_{3}$ .

Thus, according to molecular formula, in 1 mole of $Al(C_{2}H_{3}O_{2})_{3}$ there are $6\times 6.023\times 10^{23}=3.61\times 10^{24}$ atoms of oxygen atoms.

1 atom of oxygen will be present in $\frac{1}{3.61\times 10^{24}}$ moles of $Al(C_{2}H_{3}O_{2})_{3}$ . Thus,

$2.63\times 10^{24} atoms of oxygen \rightarrow \frac{2.63\times 10^{23}}{3.61\times 10^{24}}= 0.7285 moles of Al(C_{2}H_{3}O_{2})_{3}$ .

Molar mass of $Al(C_{2}H_{3}O_{2})_{3}$ is 236 g/mol, mass can be calculated as follows:

$m=n\times M=0.7285 mol\times 236 g/mol=172 g$

Therefore, mass of $Al(C_{2}H_{3}O_{2})_{3}$ will be 172 g.

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3 years ago

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