Answer:
They have different amounts of neutrons.
They have different mass numbers.
Explanation:
Carbon-12 and carbon-13 are two isotopes of the element carbon. The difference between carbon-12 and carbon-13 is the number of neutrons in each atom. Atoms of both isotopes of carbon contain 6 protons. Atoms of carbon-12 have 6 neutrons, while atoms of carbon-13 contain 7 neutrons. And because the mass number is the sum of protons and neutrons in the nucleus then will be different too. Atoms of carbon-12 have the mass number equal to 12 a.m.u. while atoms of carbon-13 have the mass number equal to 13 a.m.u. .
a.m.u. - atomic mass units
Answer:
Places near the Equator experience little seasonal variation. They have about the same amount of daylight and darkness throughout the year. These places remain warm year-round. Near the Equator, regions typically have alternating rainy and dry seasons.
Explanation:
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Empirical formula =?
Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Mass of Hydrogen (H) =?
Mass of H = mass of compound – mass of C
Mass of H = 6.32 – 5.41
Mass of H = 0.91 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of C = 5.41 g
Mass of H = 0.91 g
Divide by their molar mass
C = 5.41 / 12 = 0.451
H = 0.91 / 1 = 0.91
Divide by the smallest
C = 0.451 / 0.451 = 1
H = 0.91 / 0.451 = 2
Thus, the empirical formula for the compound is CH₂
Answer:
87.5 mi/hr
Explanation:
Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.
vf = 60 mi/hr
vi = 0 mi/hr
Δt = 8 secs
a = vf - vi/ Δt
= 60 mi/hr - 0 mi/hr/ 8 secs
= 60 mi/hr / 8 secs
= 7.5 mi/hr^2
Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.
vi = 50 mi/ hr
Δt = 5 secs
a = 7.5 mi/ hr^2
a = vf - vi/ Δt
7.5 = vf - 50 mi/hr / 5 secs
37.5 = vf - 50
87.5 mi/ hr = vf