Answer:
Number of moles of hydrogen gas produced when 15.3 g of sodium reacts with water = 0.333 moles of hydrogen gas
Explanation:
The reaction between sodium metal and water is given by the chemical equation below:
2Na(s) + 2H₂O(l) ------> 2NaOH(aq) + H₂(g)
From the equation of reaction above, 2 moles of sodium reacts with 1 mole of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen gas.
mole ratio of sodium and hydrogen gas is 2:1
molar mass of sodium =23 g/mol:
number of moles of sodium present in 15.3 g = mass/molar mass
number of moles of sodium present in 15.3 g = 15.3 g/ 23 g/mol = 0.665 moles
number of moles of hydrogen gas produced = 0.665 * 1/2 = 0.333 moles
Therefore, number of moles of hydrogen gas produced when 15.3 g of sodium reacts with water is 0.333 moles
They all have to be measured
The answer:
for the monoatomic <span>selenium ions
</span> -the ion charge of selenium is 2-, so the answer is [Se]2+
as for the monoatomic phosphorus ions
-the ion charge of phosphorus is 3-, so the answer is [P]3-
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this is a question about titration, which base solved by knowing that the HCl reacts with the NaOH in a 1:1 mole ratio, and therefore, we can write the following:
Thus, we solve for the molarity of the base, NaOH, as shown below:
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