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garik1379 [7]
3 years ago
14

If you hold your hand over a pot of boiling water, it feels hot. Explain how the boiling water is transferring heat to your hand

. Convection, because boiling water has enough energy to turn into water vapor, which rises through the air and transfers heat to your hand Conduction, because as the water boils, liquid water droplets splash out of the pot and hit your hand, transferring heat Radiation, because heat from the sun warms the top of your hand and that transfers to the water Radiation, because the heat energy moves from the pot to the air and from the air to your hand
Chemistry
2 answers:
scoray [572]3 years ago
5 0

Answer:

Convection, because boiling water has enough energy to turn into water vapour, which rises through the air and transfers heat to your hand.

Explanation:

When water boils, it forms hot water vapour (steam). The hot vapour is less dense than air, so it rises and carries its heat energy along. This process is called convection.

B is wrong. Unless the water is boiling quite vigorously, liquid water droplets do not splash out of the pot.

C is wrong. You may be indoors where the sun is not shining.

D is wrong. Radiant energy would move directly from the pot to your hand.

FinnZ [79.3K]3 years ago
3 0

Answer: by conduction, which is direct touch

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The periodic table is useful because it is organized to show many patterns and trends. What property shows a decrease moving fro
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Atomic radius

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A decrease in moving from the bottom of Group 3 to the top of the group shows an increase in trend from top to bottom.

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3 years ago
Determine the resulting pH when 12mL if 0.16M HCl are reacted with 32 mL if 0.24M KOH.
TEA [102]

Answer:

pH = 13.1

Explanation:

Hello there!

In this case, according to the given information, we can set up the following equation:

HCl+KOH\rightarrow KCl+H_2O

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

n_{HCl}=0.012L*0.16mol/L=0.00192mol\\\\n_{KOH}=0.032L*0.24mol/L=0.00768mol

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

n_{KOH}=0.00768mol-0.00192mol=0.00576mol

And the resulting concentration of KOH and OH ions as this is a strong base:

[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M

And the resulting pH is:

pH=14+log(0.131)\\\\pH=13.1

Regards!

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3 years ago
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