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marta [7]
4 years ago
13

What is the heaviest gas element

Chemistry
2 answers:
Katen [24]4 years ago
5 0
Here it is. Radon is the heaviest gas element

Mashutka [201]4 years ago
5 0

Answer:

Radon

Explanation:

n 1908 Ramsay and Gray, who named it niton, isolated the element and determined its density, finding it to be the heaviest known gas. It is essentially inert and occupies the last place in the zero group of gases in the Periodic Table. Since 1923, it has been called radon.

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What is meant by the half-life of a radioactive substance
Shtirlitz [24]

Answer:

Explanation:

The half life of a radioactive atom is the time taken for half of the radioactive nuclei to disintegrate. The shorter the half life, the faster a radioactive nuclei decays.

Half life is often expressed as:

                               Half life = \frac{0.693}{λ}

Where λ is the decay constant.

3 0
3 years ago
Hellpppppppppppppppppppppp
zlopas [31]

Answer:

SnH4

Explanation:

Because the melting point of SnH4 is higher than CH4

7 0
3 years ago
I need help with acids and bases.
Alisiya [41]

levels greater than seven are bases

levels on 7 are neutral

levels low than 7 are acids

there are 14 levels, Acids change litmus paper red and Bases change litmus paper blue.

5 0
3 years ago
Which of these is the lowest subgroup? kingdom, order, genus, or species.
olga55 [171]
The correct answer is species

6 0
3 years ago
Read 2 more answers
What is the freezing point of a solution prepared from 45.0 g ethylene glycol (C2H6O2) and 85.0 g H2O? Kf of water is 1.86°C/m.
Andrews [41]

Answer:

T_{sol}=-15.9\°C

Explanation:

Hello,

In this case, we can analyze the colligative property of solutions - freezing point depression - for the formed solution when ethylene glycol mixes with water. Thus, since water freezes at 0 °C, we can compute the freezing point of the solution as shown below:

T_{sol}=T_{water}-i*m*Kf

Whereas the van't Hoff factor for this solute is 1 as it is nonionizing and the molality is:

m=\frac{mol_{solute}}{kg\ of\ water}=\frac{45.0g*\frac{1mol}{62g} }{85.0g*\frac{1kg}{1000g} } =8.54m

Thus, we obtain:

T_{sol}=0\°C+(-8.54m*1.86\frac{\°C}{m} )\\\\T_{sol}=-15.9\°C

Best regards.

6 0
3 years ago
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