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3 years ago

Which ions in flint water caused the protective layer inside the pipes to break down?

1 answer:

6 0

The answer is Oxygen ions & Chloride ions. Although Dissolved Oxygen (DO) can not interact with the Lead, Orthophosphates have to be added continually or the barrier breaks down. If the barrier does break down, DO combines with Lead atoms, oxidizing them. It allows Lead to drain into drinking water. Once oxidized, Lead dissolves into the water instead of sticking to the pipe. Flint’s water treatment plant did not add
orthophosphates, allowing the pipes to corrode, and Lead quickly contaminated the drinking water. Additionally, Flint River water had high levels of chlorides, which accelerate corrosion.

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Write a sentence that descrices how to determine the number of moles of a compound in known mass of a

sattari [20]

Explanation:

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

For example ,

For a compound X ,

The given mass i.e. w = 20 g

and the molecular mass ,i.e. , m = 10 g / mol

Then the moles can easily be calculated by using the above formula ,

n = w / m

n = 20 g / 10 g/mol = 2 mol

Hence , answer = 2 mol.

6 0

3 years ago

2.Please study the figures below which illustrate the steps in the chemical reaction of fluoromethane (CH3F) with a hydroxide io

Monica [59]

1) The names of the molecules

2) Write the chemical equation

$OH^-+CH_3F\rightarrow CH_3OH+F^-$

3) Balance the chemical equation

1 fluoride in the reactants and 1 fluoride in the products

1 carbon in the reactants and 1 carbon in the products

4 hydrogens in the reactants and four hydrogens in the products

1 oxygen in the reactants and 1 oxygen in the products

Since the number of atoms in the reactants is the same that the number of atoms in the products, the chemical equation is balanced.

7 0

1 year ago

You wish to make a 0.299 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid

Art [367]

Answer:

$V_1=2.49mL$

Explanation:

Hello,

In this case, considering that the moles of hydrioiodic acid remain unchanged during the dilution process:

$n_{HI}=n_{HI}$

One could apply the following equality in terms of molarity:

$V_1M_1=V_2M_2$

Whereas the subscript 1 accounts for the solution before the dilution and 2 after the dilution, therefore, the required volume of 6.00 M acid is:

$V_1=\frac{V_2M_2}{M_1} =\frac{50.0mL*0.299M}{6.00M}=2.49mL$

Best regards.

5 0

3 years ago

A gaseous mixture of o2 and n2 contains 35.8 % nitrogen by mass. what is the partial pressure of oxygen in the mixture if the to

lubasha [3.4K]

The partial pressure is the amount of linguistic compound there is which makes the lagitude of the element 64.663

5 0

3 years ago

If 200 g of water is heated from 20 C to 40 C, then what is the heat added in kilocalories (same as food calories)?

Maslowich

Answer: 4Kcal

Explanation:

H= mcø

M=200g

C= 1 cal/g/°c

Ø= 40-20=20°c

H= 200*1*20= 4000calories= 4Kcal

8 0

3 years ago