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astra-53 [7]
3 years ago
15

Mass of water using isotopes? The water found on Earth is almost entirely made up of the ^1H and ^{16}O isotopes for a formula o

f H_2O and a molecular mass of 18.0 amu. What is the largest mass that a water molecule could have using other isotopes?
Chemistry
2 answers:
jenyasd209 [6]3 years ago
7 0
Thank you for posting your question here brainly. Based on the problem mentioned above the largest mass that water molecule could have using other isotopes is <span>24 amu. Below is the solution, I hope the answers helps. 

</span><span>T2_18O = 24</span>
Anettt [7]3 years ago
6 0

Answer : 24.032 amu

Explanation : The mass of water using isotopes can be found by replacing the hydrogen element with its isotope called tritium which has mass of 3.016 amu.

Tritium (T) contains one proton and two neutrons in it. When the water is replaced by tritium the mass of the water becomes as;

T_{2}O = {(3.016 x 2) + 18} = 24.032 amu.

whereas in H_{2}O = {(1 x 2) + 18} = 20 amu.

So, the mass of water will be highest when we replace, hydrogen by tritium as the isotope.

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It’s a polyatomic and it has a negative charge. It’s located in the nucleus of the atom, along with the protons.
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3 years ago
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Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
Phoenix [80]

Answer:

pH = 8.0

Explanation:

First, we have to calculate the moles of NaOH.

35.8 \times 10^{-3}L.\frac{0.020mol}{L} =7.2\times 10^{-4}mol

Let's consider the balanced equation.

C₂H₄O₃ + NaOH ⇒ C₂H₃O₃Na + H₂O

The molar ratio C₂H₄O₃: NaOH: C₂H₃O₃Na is 1: 1: 1. So, when 7.2 × 10⁻⁴ moles of NaOH react completely with 7.2 × 10⁻⁴ moles of C₂H₄O₃ they form 7.2 × 10⁻⁴ moles of C₂H₃O₃Na.

The concentration of C₂H₃O₃Na is:

\frac{7.2\times 10^{-4}mol}{60.8 \times 10^{-3}L} =0.012M

C₂H₃O₃Na dissociates according to the following equation:

C₂H₃O₃Na(aq) ⇒ C₂H₃O₃⁻(aq) + Na⁺(aq)

C₂H₃O₃⁻ comes from a weak acid so it undergoes basic hydrolisis.

C₂H₃O₃⁻ + H₂O ⇄ C₂H₄O₃ + OH⁻

If we know that pKa for C₂H₄O₃ is 3.9, we can calculate pKb for C₂H₃O₃⁻ using the following expression:

pKa + pKb = 14

pKb = 14 -3.9 = 10.1

10.1 = -log Kb

Kb = 7.9 × 10⁻¹¹

We can calculate [OH⁻] using the following expression:

[OH⁻] = √(Kb.Cb)               <em>where Cb is the initial concentration of the base</em>

[OH⁻] = √(7.9 × 10⁻¹¹ × 0.012M) = 9.7 × 10⁻⁷ M

Now, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (9.7 × 10⁻⁷) = 6.0

pH + pOH = 14

pH = 14 - pOH = 14 - 6.0 = 8.0

7 0
3 years ago
Consider the following electronegativity values:
luda_lava [24]

Answer: option C. HF

Explanation: A polar bond is a covalent bond between two atoms where the electrons forming the bond are unequally distributed. Fluorine is more electronegative than hydrogen so the electrons in the bond are more closely associated with the fluorine atom than with the hydrogen atom.

7 0
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The element that gains electrons, becomes reduced.

While the one which loses electrons, becomes oxidized.

In this equation,

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By balancing the equation, we will get:

3CH₃OH + Cr₂O₇²⁻ + 8H⁺ --> 3CH₂O + 2Cr³⁺ + 7H₂O

Here the oxidation state of Cr changes from +6 to +3 that is it is being reduced thus serving as a oxidizing agent while other element retain their charges.

Here Cr₂O₇²⁻ is reduced while CH₃OH is oxidized.

So Cr₂O₇²⁻ serves as a oxidizing agent, while CH₃OH serves as reducing agent .

4 0
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katovenus [111]

Answer:

Yes

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Masses for the three subatomic particles can be expressed in amu (atomic mass units) or grams. For simplicity, we will use the amu unit for the three subatomics. Both neutrons and protons are assigned as having masses of 1 amu each.

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