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3 years ago

Help me please.......................................................................

Mathematics

2 answers:

podryga [215]3 years ago

7 0

Substitute the value if <em>t.
</em>49/7=7
7 is the answer.

yulyashka [42]3 years ago

4 0

T = 49, so 49 divided by 7 = 7.

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A cookie recipe calls for 1 2/3 of sugar if you plan on changing the recipe to make it 2 1/2 times as much how many cups of suga

Dimas [21]

Answer:

$4\frac{1}{6}\ cups$

Step-by-step explanation:

we know that

The recipe calls for 1 2/3 of sugar

To make 2 1/2 times the recipe

Multiply 2 1/2 by 1 2/3

Convert mixed numbers to an improper fraction

$1\frac{2}{3}=\frac{1*3+2}{3}=\frac{5}{3}\ cups$

$2\frac{1}{2}=\frac{2*2+1}{2}=\frac{5}{2}$

$\frac{5}{2}(\frac{5}{3})=\frac{25}{6}\ cups$

Convert to mixed number

$\frac{25}{6}=\frac{24}{6}+\frac{1}{6}=4\frac{1}{6}\ cups$

8 0

3 years ago

A recipe uses 1/2 tablespoon of sugar for every 1 1/2 cups of oatmeal. How many tablespoons are used for each cup of oatmeal?

kherson [118]

1/2 tsp bc 1/3 of 1 1/2 is 1/2

8 0

3 years ago

Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if

Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

Reflexivity: If $\forall x \in A, x \rightarrow x$
Symmetry: $\forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x$
Transitivity: $\forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z$

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0

3 years ago

NEED HELP ASAP !! MARKIN BRAINIEST !!<br><br> btw the choices for all of em are is not or is

yulyashka [42]

answers are

is not

8 0

3 years ago

In a shipment of 71 vials, only 13 do not have hairline cracks. If you randomly select 2 vials from the shipment, what is the pr

yanalaym [24]

Answer:

0.0313

Step-by-step explanation:

Given that in the shipment of 71 vials, only 13 do not have hairline cracks

Probability of not having a hairline cracks = $\frac{13}{71}$

If you randomly select 2 vials from the shipment

(Probability of not having a hairline cracks)' = $\frac{13-1}{71-1}$ = $\frac{12}{70}$

what is the probability that none of the 2 vials have hairline cracks.

i.e $(\frac{13}{71}) * (\frac{12}{70})$

= 0.183 × 0.171

= 0.0313

Hence, the probability that none of the 2 vials have hairline cracks = 0.0313

6 0

3 years ago