Answer:
1.36x10^10L
Explanation:
Step 1:
Determination of the mole of fluorine that contains 3.66x10^32 molecules. This is shown below:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This implies that 1 mole of fluorine also contains 6.02x10^23 molecules.
Now if 1 mole of fluorine contains 6.02x10^23 molecules,
Therefore, Xmol of fluorine will contain 3.66x10^32 molecules i.e
Xmol of fluorine = 3.66x10^32/6.02x10^23
Xmol of fluorine = 6.08x10^8 moles
Step 2:
Determination of the volume occupied by 6.08x10^8 moles of fluorine.
1 mole of any gas occupy 22.4L at stp. This means that 1 mole of fluorine also occupy 22.4L at stp.
Now if 1 mole of fluorine occupies 22.4L at stp,
Then 6.08x10^8 moles of fluorine will occupy = 6.08x10^8 x 22.4 = 1.36x10^10L
Answer: 0.176 atm
Explanation: Solution attached:
Use Boyle's Law to find the new pressure of the gas.
P1V1 = P2V2
Derive for P2
P2 = P1V1 / V2
= 5.5 atm ( 4.8 L ) / 150 L
= 0.176 atm
Answer:
0.0185 min⁻¹
Explanation:
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
Given:
20.0 % of the initial values is left which means that 0.20 of is left. So,
![\frac {[A_t]}{[A_0]}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D)
= 0.20
t = 87.0 min
![\frac {[A_t]}{[A_0]}=e^{-k\times t}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%3De%5E%7B-k%5Ctimes%20t%7D)
<u>k = 0.0185 min⁻¹</u>
Molarity (M) = moles of the solute (mol) / Volume of the solution (L)
The molarity of the given KCl solution = 2.10 M
Volume of the given KCl solution = 85.0 mL
Hence,
2.10 M = Moles of KCl / 85.0 x 10⁻³ L
Moles of KCl = 2.10 M x 85.0 x 10⁻³ L
= 0.1785 mol
Moles (mol) = Mass (g) / Molar mass (g mol⁻¹)
Molar mass of KCl = 74.56 g mol⁻¹
Hence,
0.1785 mol = Mass of KCl / 74.56 g mol⁻¹
Mass of KCl = 0.1785 mol x 74.56 g mol⁻¹
= 13.30 g
Hence, mass of given KCl in 85.0 mL is 13.30 g.
Answer:
<h2>5.49</h2>
Explanation:
The pH of a solution can be found by using the formula
![pH = - log ([ { H_3O}^{+}])](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%28%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D%29)
H3O+ is the hydronium ion
From the question we have
We have the final answer as
<h3>5.49 </h3>
Hope this helps you
