The balanced chemical reaction is written as:
<span>2K + F2 ---> 2 KF
We are given the amount of potassium metal to be used in the reaction. This will be the starting point for the calculation. We do as follows:
23.5 g K ( 1 mol / 39.1 g ) ( 1 mol F2/2 mol K ) ( 22.4 L / 1 mol ) = 13.46 L F2
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Explanation:
Since, some of the given sample is stuck inside and behind the pipet. Hence, there will occur a decrease in the percent of acetic acid.
This is because a decrease in concentration of the acid will also lead to a decrease in the amount of sample taken for the estimation. Since. lesser is the amount or concentration present lesser will be its analyte concentration.
For example, we took 10 mg of a pickel sample but 3 mg of the sample remain stuck in the pipet. This means we actually titrating a sample less than 10 mg.
Therefore, the analyte concentration in the pickel will also be less.
This is a one-step unit analysis problem. Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.
1 mole is equal to 6.022x10²³ particles as given, so:
<h3>
Answer:</h3>
2.49 mol
Let me know if you have any questions.
Answer:
63.9 grams. Yes, the Nacl was converted. Maximum possible ppm is 540ppm.
Explanation:
I this is college level chemistry not regular high school chem.
