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mash [69]
3 years ago
14

1.Build or draw the Lewis structure for each of the molecules listed below.

Chemistry
1 answer:
bagirrra123 [75]3 years ago
5 0
This may help you

Allright for <span><span>H2</span>O:</span> - The central atom is? --> the oxygen atom - How many atoms are bonded to the central atom? --> 2 hydrogen atoms - How many lone pairs of electrons are on the central atom? --> O has 6 electrons and has 2 single bonds, so 2 pairs - How many single bonds are there in this molecule? --> 2 - How many multiple bonds (double and/or triple) are there in this molecule? --> none For each of your molecules, answer the following questions: 1. Determine the electronegativity between the atoms of each molecule. Electronegativity O = 3.44 Electronegativity H = 2.20 3.44-2.20=1.24, so the electronegativity between O and H = 1.24 2. Identify the bond as either ionic or covalent. Electronegativity of 0.0-1.7 = covalent Electronegativity of 1.7-3.3 = ionic So it's a covalent bond 3. State whether the molecule is polar or non polar. Electronegativity of 0.5-1.7= polar covalent 4. Identify the structure as having hydrogen bonding, dipole-dipole moments or London dispersion forces (LDF). <span><span>H2</span>O</span><span> = hydrogen bonding</span>
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When aqueous solutions of potassium cyanide and hydrobromic acid are mixed, an aqueous solution of potassium bromide and hydrocy
mrs_skeptik [129]

Answer:

hey there

Explanation:

CN- (aq) + H+ (aq) → HCN(I)

The reactants are aqueous solutions:

NaCN(aq) and HBr(aq)

When you mix these compounds you make pure HCN (I)

The molecular equation is:

NaCN(aq) + HBr(aq) → NaBr(aq) + HCN(I)

When you dissociate the reactants, you have: Nat(aq) +CN¯(aq) + H*(aq) + Br−(aq) → Nat(aq) + ->

Br (aq) + HCN(I)

Sodium bromide, it is a salt, that can also be

dissociated in the solution

To make, the net ionic equation you remove the repeated ions

CN- (aq) + H+ (aq) → HCN(I)

If you like my answer please mark as brainliest

8 0
2 years ago
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