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77julia77 [94]
3 years ago
10

Write the chemical formula for the anion present in the aqueous solution of cuso4.

Chemistry
2 answers:
mamaluj [8]3 years ago
8 0

Answer : The chemical formula for the anion present in the aqueous solution of CuSO_4 is, SO_4^{2-}

Explanation :

The chemical formula of copper sulfate is, CuSO_4.

The dissociation reaction of CuSO_4 in aqueous solution will be:

CuSO_4(aq)\rightarrow Cu^{2+}(aq)+SO_4^{2-}(aq)

From the reaction we conclude that, 1 mole of CuSO_4 dissociate in solution to give 1 mole of Cu^{2+} ion (copper ion) and 1 mole of SO_4^{2-} ion (sulfate ion).

In the reaction, Cu^{2+} ion (copper ion) is a cation and SO_4^{2-} ion (sulfate ion) is an anion.

Hence, the chemical formula for the anion present in the aqueous solution of CuSO_4 is, SO_4^{2-}

ki77a [65]3 years ago
6 0
SO4 -2, or Sulfate

Hope this helps! :)
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Explanation:

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8 0
3 years ago
From observing the plant and animal cell diagrams above, which cell seemed to have more of a regular structure?
Tasya [4]

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4 0
2 years ago
How does a buffer resist change in pH upon addition of a strong acid? The strong acid reacts with the strong base in the buffer
MrRa [10]

Answer:

The strong acid reacts with the weak base in the buffer to form a weak acid, which produces few H+ ions in solution and therefore only a little change in pH.

Explanation:

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4 0
3 years ago
How many moles are in 1.806 x 1024 molecules of bromine?
Pepsi [2]
<h3>Answer:</h3>

2.999 mol Br

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.806 × 10²⁴ molecules Br

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 1.806 \cdot 10^{24} \ molecules \ Br(\frac{1 \ mol \ Br}{6.022 \cdot 10^{23} \ molecules \ Br} ) = 2.999 mol Br

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

Our final answer is already in 4 sig figs, so there is no need to round.

7 0
3 years ago
Read 2 more answers
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