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cupoosta [38]
3 years ago
15

What is 7.25 in word form

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer: seven and twenty-five hundredths


Step-by-step explanation:

just need to know how to say it

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Find the sum<br>7/8+3/4 ​
ICE Princess25 [194]

Answer as an improper fraction =  13/8

This is equivalent to the mixed number   1 & 5/8

In decimal form, 13/8 = 1.625

=========================================

Work Shown:

3/4 = (3/4)*(2/2)

3/4 = (3*2)/(4*2)

3/4 = 6/8

----------

7/8 + 3/4

7/8 + 6/8

(7+6)/8

13/8

So 7/8 + 3/4 = 13/8

4 0
3 years ago
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What is the measure of ZBVE?A2608751V8moRA. 75°B. 1350C. 60°D. 45°
Gekata [30.6K]

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7 0
1 year ago
Find the sum of all the prime numbers between 20 and 40.
Helga [31]

Answer:

120

Step-by-step explanation:

yw dude

3 0
3 years ago
SOMEONE PLEASE HELP ME WITH THIS AND EXPLAIN EACH ONE AND HOW YOU DID IT PLEASE MY TEACHER SUCK AND ILL GIVE YOU BRAINLY IF U GE
valentinak56 [21]

Answer:

a)

d)

Step-by-step explanation:

It's easiest to reduce each statement to its simplest form for comparison

Our test statement can be reduced by combining like terms

16x - 12 -24x + 4 = -8x - 8

this becomes our new gold standard

a) 4 + 16x - 12(1 + 2x)

apply the distributive property by multiplying terms in parenthesis by -12

4 + 16x - 12 - 24x

combine terms

-8x - 8     Yeaah, We have a winner as it exactly matches our gold standard.

b) 40x - 16 is already in simplest terms and does NOT match the gold standard.

c) 16x - 24x - 4 + 12

has the same cardinal values as the original, but differing signs, reducing gives -8x + 8

Not quite the same as a plus sign occurs where a negative exists in our gold standard.

d) -8x - 8  is already in simplest terms and exactly matches our gold standard. Yeah!

e) 10(1.6x - 1.2 - 2.4x + 4)

apply distributive property by multiplying each term in parenthesis by 10

16x - 12 - 24x + 40

combine like terms

-8x + 28 does NOT match our gold standard

5 0
2 years ago
Using a proportion, what can you infer about the number of households in her town that have more than three children?
eduard

Answer:

About 296 households have more than three children.

Step-by-step explanation:

The complete question is:

Carmen used a random number generator to simulate a survey of how many children live in the households in her town. There are 1,346 unique addresses in her town with numbers ranging from zero to five children. The results of 50 randomly generated households are shown below. Children in 50 Households Number of Children Number of Households 0 5 1 11 2 13 3 10 4 9 5 2 Using a proportion, what can you infer about the number of households in her town that have more than three children? About 242 households have more than three children. About 269 households have more than three children. About 296 households have more than three children. About 565 households have more than three children.

Solution:

The data provided for the number of children and number of households is:

Number of Children (<em>X</em>)          Number of Households (<em>f</em> (X))

               0                                                   5

               1                                                    11

               2                                                   13

               3                                                   10

               4                                                    9

               5                                                    2

           TOTAL                                             50

Compute the probability of households having more than three children as follows:

P (More than 3 children) = P (4 children) + P (5 children)

                                        =\frac{9}{50}+\frac{2}{50}

                                        =\frac{11}{50}

                                        =0.22

Let the random variable <em>Y</em> be defined as the number of households having more than three children.

The probability of the random variable <em>Y </em>is, <em>p</em> = 0.22.

The entire population, i.e. total number of addresses in Carmen's town with numbers ranging from zero to five children, consists of <em>N</em> = 1,346 households.

Compute the expected number of households having more than three children as follows:

E(Y) =N\times p

         =1346\times 0.22\\=296.12\\\approx 296

Thus, about 296 households have more than three children.

4 0
3 years ago
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