Answer:
Step-by-step explanation:
Subtract 2x
from both sides of the equation.
y=8−2x
x−y=2
Replace all occurrences of y
in x−y=2 with 8−2x
.
y=8−2x
x−(8−2x)=2
Simplify the left side.
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y=8−2x
3x−8=2
Solve for x
in the second equation.
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y=8−2x
x=103
Replace all occurrences of x
in y=8−2x with 103
.
y=8−2(103)
x=103
Simplify 8−2(103)
.
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y=43
x=103
The solution to the system of equations can be represented as a point.
(103,43)
Answer:
x <= 5 is the answer
Step-by-step explanation:
Because the arrow is pointinng the direction of the color
Integer
Rational
(its not a whole number. Whole numbers are 0 or positive.)
<span>Starting position:
Let B start at origin(O) & A is at (-150 ,0) ie 150 km west of the origin . At 3pm , t= 0
A is changing its position at ( 150-35t) km/h
& B is changing its position at 25t km/h
Therefore
AB^2 = OA^2 + OB^2 /// Pythagoras Theorem
= (150-35t)^2 + ( 25t)^2
= 22 500 - 10 500 t + 1225t^2 +625t^2
= 22 500 - 10 500t + 1850t^2
AB = ( 22 500 - 10 500t + 1850t^2)^1/2
d (AB) /dt = 1/2 * ( 22 500 - 10 500t + 1850t^2)^-1/2 * ( - 10 500 + 3700t)
= ( - 5250 + 1850t) / ( 22 500 - 10 500t + 1850t^2)^1/2
At 3pm , t=0
At 7pm , t= 4
So d (AB) /dt = ( -5250 + 1850*4) / ( 22500 - 10500*4 + 1850*4^2)^1/2
= 2150 / 100.5
= 21.4 km/hr
</span>The distance between the ships changing at 7 P.M. is with a speed of 21.4 km/hr.
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