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madreJ [45]
3 years ago
14

I don't seem to understand this problem may you guys help me :)

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0
Let x represent the number of cartons of strawberry ice cream and y represent the number of cartons of chocolate ice cream.

Total cost of ice cream = 3.79x + 3.79y

Equivalent expression = 3.79(x + y)
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X 12 = 6 10 give your answer as an improper fraction in its simplest form.
Alika [10]

Answer:

41/6

Step-by-step explanation:

Take the root of both sides and solve.

3 0
2 years ago
I need help !!! I don’t understand the problem
Pepsi [2]

Answer:

It would be -81²x+81x-18= -9x+6

Step-by-step explanation:

When you work equation one you get 18. Then when you work equation two, you get -2/3=-0.666666667

7 0
3 years ago
Given sin B = .91 find angle B in radians. Round your answer to the nearest hundredth.
pochemuha
 You could better find the answer at 
https://answers.yahoo.com/question/index?qid=20110628190101AAKUGSE
where someone else has already figured it out
8 0
3 years ago
Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p
kvv77 [185]

The question is an illustration of composite functions.

  • Functions c(n) and h(n) are \mathbf{c(n) = 5000 + 250n} and \mathbf{n(h) = 5h}
  • The composite function c(n(h)) is \mathbf{c(n(h)) = 5000 + 1250h}
  • The value of c(n(100)) is \mathbf{c(n(100)) = 130000}
  • The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

  • $5000 in fixed costs plus an additional $250
  • 5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

\mathbf{c(n) = Fixed + Additional \times n}

This gives

\mathbf{c(n) = 5000 + 250 \times n}

\mathbf{c(n) = 5000 + 250n}

The function for number of systems is:

\mathbf{n(h) = 5 \times h}

\mathbf{n(h) = 5h}

<u>(b) Function c(n(h))</u>

In (a), we have:

\mathbf{c(n) = 5000 + 250n}

\mathbf{n(h) = 5h}

Substitute n(h) for n in \mathbf{c(n) = 5000 + 250n}

\mathbf{c(n(h)) = 5000 + 250n(h)}

Substitute \mathbf{n(h) = 5h}

\mathbf{c(n(h)) = 5000 + 250 \times 5h}

\mathbf{c(n(h)) = 5000 + 1250h}

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

\mathbf{c(n(100)) = 5000 + 1250 \times 100}

\mathbf{c(n(100)) = 5000 + 125000}

\mathbf{c(n(100)) = 130000}

<u>(d) Interpret (c)</u>

In (c), we have: \mathbf{c(n(100)) = 130000}

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0
3 years ago
Which is the equation of a line that has a slope of 1 and passes through point (5, 3)?
max2010maxim [7]

Answer:

y = x - 2

Step-by-step explanation:

y = x + b

3 = 5 + b

y = x - 2

8 0
3 years ago
Read 2 more answers
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