Question

Calculate the rotational energy of a segment, given mass of the segment is 2.2 kg, moment of inertia is 0.57 kg-m2, and angular velocity is 25 rad/s.

Answer 1

To solve this problem we will use the concepts given by the rotational kinetic energy which describes the energy in a body product of its moment of inertia and its angular velocity, mathematically this is given as,

$KE = \frac{1}{2} I\omega^2$

Where,

I = Moment of Inertia

$\omega$= Angular Velocity

Replacing with our values we have that,

$KE = \frac{1}{2} (0.57)(25)^2$

$KE = 178.125J T$

Therefore the rotational energy is 178.125J