Answer:
<h3>The answer is 3.38 m/s²</h3>Explanation:
The acceleration of an object given it's velocity and time taken can be found by using the formula
where
a is the acceleration
v is the velocity
t is the time
From the question
v = 27 m/s
t = 8 s
We have
We have the final answer as
<h3>3.38 m/s²</h3>Hope this helps you
Answer:
m/s
Explanation:
Assumptions: 0° is true North, and 90° is east (along the x-axis).
To solve this problem we must use the expression:
Where is the velocity in the y-direction (East),
is the total velocity in the direction which the aircraft is travelling, and
is the direction the aircraft is travelling (angle from the y-axis).
Using the equation above, we obtain the y-component of velocity
m/s which is rounded to 227 m/s (due to the number of significant figures in the question).
Answer:
Explanation:
Our values are
We can find the time through
The expression for the distance between the Earth and the spaceship is as follow:
Where c is Light speed, and t our previous time.
Therefore the distance between the Eath and the Spaceship is m
Answer:
The time taken is
Explanation:
From the question we are told that
The length of the speed ramp is
The speed of the speed ramp is
The time taken to cover the distance is
The walking speed( when not on the speed ramp) required to cover the 104m is mathematically represented as
Substituting values
The speed required to cover the 104m distance when on a speed speed ramp is mathematically represented as
substituting values
Now the time taken to travel the 104m distance when walking on the speed ramp is mathematically evaluated as