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MariettaO [177]
3 years ago
7

What is required for force to come into play​

Physics
1 answer:
White raven [17]3 years ago
7 0

Answer:

An interaction of one object with another object results in a force between the two objects. Thus, at-least two objects must interact for a force to come into play.

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What substances help muscles move
harkovskaia [24]
Together, our bones, muscles, and joints along with tendons, ligaments, and cartilage form our musculoskeletal system and enable us to do everyday physical activities
8 0
4 years ago
Let T be a linear transformation from a vector space V with dimension 11 onto a vector space W with dimension 7. What is the dim
erica [24]

Answer:

The dimension of the nullspace of T = 4

Explanation:

The rank/dimension theorem is explains that:

Suppose V and W are vector spaces over F, and T:V → W is linear. If V is finite dimensional, then

nullity(T) + rank(T) = dim(V).

rank(T) = dimension of T = dim(T) = dim(W) = 7

nullity(T) = dimension of the nullspace of T = dim(T) = ?

dim(V) = 11

nullity(T) = dim(V) - dim(T) = 11 - 7

nullity(T) = 4.

8 0
4 years ago
What are some examples for number 4?
lidiya [134]

I would love to help you, but the picture is in a difficult position to read.

5 0
4 years ago
In need of some help here
Cloud [144]

Answer:

need more context!

Explanation:

7 0
3 years ago
You are traveling on an interstate highway at the posted speed limit of 70 mph when you see that the traffic in front of you has
vovikov84 [41]

Answer:8.75 s,

136.89 m

Explanation:

Given

Initial velocity=70 mph\approx 31.29 m/s

velocity after 5 s is 30 mph\approx 13.41 m/s

Therefore acceleration during these 5 s

a=\frac{v-u}{t}

a=\frac{13.41-31.29}{5}=-3.576 m/s^2

therefore time required to stop

v=u+at

here v=final velocity =0 m/s

initial velocity =31.29 m/s

0=31.29-3.576\times t

t=\frac{31.29}{3.576}=8.75 s

(b)total distance traveled before stoppage

v^2-u^2=2as

0^2-31.29^2=2\times (-3.576)\cdot s

s=136.89 m

3 0
3 years ago
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