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MariettaO [177]
3 years ago
7

What is required for force to come into play​

Physics
1 answer:
White raven [17]3 years ago
7 0

Answer:

An interaction of one object with another object results in a force between the two objects. Thus, at-least two objects must interact for a force to come into play.

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If a honeybee is flying 7.0 m/s, what is the kinetic energy (Joules) if its mass is 0.1 g?
svetlana [45]

Answer:

KINETIC ENERGY=K.E=0.00245 Joules ≈ 0.003 Joules

Explanation:

mass=m=0.1g=0.0001kg

velocity=v=7.0m/s

kinetic energy=K.E.=?

as we know that

kinetic energy=\frac{1}{2}mv^2\\ putting values\\kinetic energy=\frac{1}{2}(0.0001kg)(7.0m/s)^2\\ kinetic energy=\frac{1}{2} 0.0049joules\\kinetic energy= 0.00245Newton meter or joules

hope it will help ^_^

5 0
3 years ago
You are classifying an organism that is unfamiliar to you.
MatroZZZ [7]

Answer:

I know that we can identify it

Explanation:

C. structure

4 0
3 years ago
Read 2 more answers
55. (III) A uniform circular plate of radius 2R has a circular hole of radius R cut out of it. The center of the smaller circle
Aleksandr [31]

Answer:

P = 0.27R from the center

Explanation:

Given,

The radius of the uniform circular plate, R = 2R

The radius of the hole, r = R

The center of the smaller circle from the center is, d = 0.8R

The center of mass of a circular disc with a hole in it given by the formula

                               P = dr²/R² - r²

Where P is the distance from the center of mass located in the line joining the two centers opposite to the hole.

Substituting the given values in the above equation,

                               P = 0.8R x R² / 4R² - R²

                                  = 0.27R³/R²

                                  = 0.27R

Hence the center of mass of plate is at a distant  P = 0.27R from the center

6 0
3 years ago
Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial spe
tia_tia [17]

Answer:

(1) 14.12 m/s

Explanation:

Given:

  • u = initial speed of the ball = 16 m/s
  • \theta = angle of the initial speed with the horizontal axis = 28^\circ
  • y_i = initial height of the ball from where Julie throws the ball = 1.5 m
  • y_f = final position of the ball where Sarah catches the ball = 1.5 m

Let us assume the following:

  • u_x = horizontal component of the initial speed
  • u_y = vertical component of the initial speed
  • a_x = horizontal acceleration of the ball
  • a_y = vertical acceleration of the ball

The given problem is projectile motion. When the ball is thrown from the air with a speed of 16 m/s at an angle 28 degree with the horizontal axis. When the ball is in the air, it experiences an only gravitational force in the downward direction if we ignore air resistance on the ball.

This means if we break the motion of the ball along two axes and study it, we have a uniform acceleration motion in the vertical direction and a zero acceleration motion along the horizontal.

Since the ball has a zero acceleration motion along the horizontal axis, the ball must have a constant speed along the horizontal at all instant of time.

Let us find out the initial velocity horizontal component of the velocity of the ball. which is given by:

u_x = u\cos 28^\circ = 16\times \cos 28^\circ = 14.12\ m/s

As this horizontal velocity remains constant in the horizontal motion at all instants of time. So, the horizontal component of the ball's velocity when Sarah catches the ball is 14.12 m/s.

Hence, the horizontal component of the ball's velocity when the ball is caught by Sarah is 14.12 m/s.

6 0
3 years ago
Read 2 more answers
Part A
Blababa [14]

Answer:

The wavelength decreases as the electron speeds up. The wavelength increases as the electron slows down.

Explanation:

5 0
3 years ago
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