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MariettaO [177]
3 years ago
7

What is required for force to come into play​

Physics
1 answer:
White raven [17]3 years ago
7 0

Answer:

An interaction of one object with another object results in a force between the two objects. Thus, at-least two objects must interact for a force to come into play.

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What is E of a hydrogen atom in the 3p state?
notsponge [240]

Answer:

E=-1.51 eV.

L=\hbar\sqrt{2}

Explanation:

The nth level energy of a hydrogen atom is defined by the formula,

E_{n}=-\frac{13.6}{n^{2} }

Given in the question, the hydrogen atom is in the 3p state.

Then energy of n=3 state is,

E_{n}=-\frac{13.6}{(3)^{2} }\\E_{n}=-1.51eV

Therefore, energy of the hydrogen atom in the 3p state is -1.51 eV.

Now, the value of L can be calculated as,

L=\hbar\sqrt{l(l+1)}

For 3p state, l=1

L=\hbar\sqrt{1(1+1)}\\L=\hbar\sqrt{2}

Therefore, the value of L of a hydrogen atom in 3p state is L=\hbar\sqrt{2}.

4 0
3 years ago
A solenoid with an inductance of 8 mH is connected in series with a resistance of 5 Ω and an EMF forming a series RL circuit. A
monitta

Answer:

induced EMF = 240 V

and by the lenz's law  direction of induced EMF is opposite to the applied EMF

Explanation:

given data

inductance = 8 mH

resistance = 5 Ω

current = 4.0 A

time t = 0

current grow = 4.0 A to 10.0 A

to find out

value and the direction of the induced EMF

solution

we get here induced EMF of induction is express as

E = - L \frac{dI}{dt}    ...................1

so E = - L \frac{I2 - I1}{dt}

put here value we get

E = - 8 × 10^{-3} \frac{10 - 4}{0.2*10^{-3}}

E = -40 ×  6

E = -240

take magnitude

induced EMF = 240 V

and by the lenz's law we get direction of induced EMF is opposite to the applied EMF

5 0
3 years ago
An 84.0 kg sprinter starts a race with an acceleration of 1.76 m/s2. If the sprinter accelerates at that rate for 11 m, and then
gulaghasi [49]

Answer:

t=17.838s

Explanation:

The displacement is divided in two sections, the first is a section with constant acceleration, and the second one with constant velocity. Let's consider the first:

The acceleration is, by definition:

a=\frac{dv}{dt}=1.76

So, the velocity can be obtained by integrating this expression:

v=1.76t

The velocity is, by definition: v=\frac{dx}{dt}, so

dx=1.76tdt\\x=1.76\frac{t^{2}}{2}.

Do x=11 in order to find the time spent.

11=1.76\frac{t^2}{2}\\ t^2=\frac{2*11}{76} \\t=\sqrt{12.5}=3.5355s

At this time the velocity is: v=1.76t=1.76*3.5355s=6.2225\frac{m}{s}

This velocity remains constant in the section 2, so for that section the movement equation is:

x=v*t\\t=\frac{x}{v}

The left distance is 89 meters, and the velocity is 6.2225\frac{m}{s}, so:

t=\frac{89}{6.2225}=14.303s

So, the total time is 14.303+3.5355s=17.838s

7 0
2 years ago
The ph of an acidic substance ia between what values on the ph scale
aalyn [17]

0 - 6 is acidic

7 is neutral

8 - 14 is basic

7 0
2 years ago
A 7.99 g sample of hcn is found to contain 0.296 g of h and 4.14 g of n.Find the mass of carbon in a sample of hcn with a mass o
Thepotemich [5.8K]

<u>Answer:</u>

Mass of C in 3.40 g of HCN =1.51 gram.

<u>Explanation:</u>

  Mass of sample of HCN = 7.99 g

  Mass of H in 7.99 g of HCN = 0.296 g

  Mass of N in 7.99 g of HCN = 4.14 g

  Mass of C in 7.99 g of HCN = (7.99-0.296-4.14) = 3.554 g

  Now mass of HCN = 3.40 g

  Mass of C in 3.40 g of HCN = \frac{3.554}{7.99} *3.40 =1.51 g

 So mass of C in 3.40 g of HCN =1.51 gram.

3 0
3 years ago
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