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ziro4ka [17]
3 years ago
8

PLEAS HELP A football player kicks a ball with a mass of 0.42 kg. The average acceleration of the football was 14.8 m/s². How mu

ch force did the kicker supply to the football? 6.22 m/s² 35.24 m/s² 6.22 N 35.24 N
Physics
2 answers:
Orlov [11]3 years ago
6 0

Answer:

The force that the football play kicked the ball with was 6.22n

Explanation:

The reason why it is 6.22N is because when you use the formula, F =MA

and you plug the numbers in, it eaquals 6.22n.

F=0.42*14.8

weqwewe [10]3 years ago
6 0

Answer:

sry im so late :(

Explanation:

the answer is 6.22 N. you use the formula F = MA. hope it helps :)

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A driver enters a one-lane tunnel at 34.4 m/s. The driver then observes a slow-moving van 154 m ahead travelling (in the same di
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Answer:

Ans. B) 22 m/s (the closest to what I have which was 20.16 m/s)

Explanation:

Hi, well, first, we have to find the equations for both, the driver and the van. The first one is moving with constant acceleration (a=-2m/s^2) and the van has no acceletation. Let´s write down both formulas so we can solve this problem.

X(van)=5.65t+154

X(driver)=34.4t+\frac{(-2)t^{2} }{2}

or by rearanging the drivers equation.

X(driver)=34.4t+t^{2}

Now that we have this, let´s equal both equations so we can tell the moment in which both cars crashed.

X(van)=X(driver)

5.65t+154=34.4t-t^{2}

0=t^{2} -(34.4-5.65)t+1540=t^{2} -28.75t+154

To solve this equation we use the following formulas

t=\frac{-b +\sqrt{b^{2}-4ac } }{2a}

t=\frac{-b +\sqrt{b^{2}-4ac } }{2a}

Where a=1; b=-28.75; c=154

So we get:

t=\frac{28.75 +\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=21.63st=\frac{28.75 -\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=7.12s

At this point, both answers could seem possible, but let´s find the speed of the driver and see if one of them seems ilogic.

V(driver)=V_{0} +at}

V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(7.12s)=20.16\frac{m}{s}V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(21.63s)=-8.86\frac{m}{s}

This means that 21.63s will outcome into a negative speed, for that reason we will not use the value of 21.63s, we use 7.12s and if so, the speed of the driver when he/she hits the van is 20.16m/s, which is closer to answer  A).

Best of luck

8 0
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