Should the size of the test charge compare to the amount of charge that produces the field

HELPPP PLS BESTIES A pattern of stars that has been named is called a constellation. One winter evening, Jason found the star ca

Damm [24]

Answer:

D) Since the stars would move from East to West just as the Sun and Moon do.

5 0

3 years ago

Why is traveling between the stars (by creatures like us) difficult?

mariarad [96]

Answer:

Stars are at large distances that even light takes thousands of years to reach us from there.

for example, alpha centauri is 4300 light years away from earth and it is considered the nearest star to us, this means that light from there takes 4300 years to reach us and with a spaceships that can move with the speed of light is would take us 4300 years to get there which is imposible to live for that long.

hence, it is difficult to move between the stars.

4 0

3 years ago

A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and

garri49 [273]

Answer:

(a) t = 1.14 s

(b) h = 0.82 m

(c) vf = 7.17 m/s

Explanation:

(b)

Considering the upward motion, we apply the third equation of motion:

$2gh = v_f^2 - v_i^2$

where,

g = - 9.8 m/s² (-ve sign for upward motion)

h = max height reached = ?

vf = final speed = 0 m/s

vi = initial speed = 4 m/s

Therefore,

$(2)(9.8\ m/s^2)h = (0\ m/s)^2-(4\ m/s)^2\\$

h = 0.82 m

Now, for the time in air during upward motion we use first equation of motion:

$v_f = v_i + gt_1\\0\ m/s = 4\ m/s + (-9.8\ m/s^2)t_1\\t_1 = 0.41\ s$

(c)

Now we will consider the downward motion and use the third equation of motion:

$2gh = v_f^2-v_i^2$

where,

h = total height = 0.82 m + 1.8 m = 2.62 m

vi = initial speed = 0 m/s

g = 9.8 m/s²

vf = final speed = ?

Therefore,

$2(9.8\ m/s^2)(2.62\ m) = v_f^2 - (0\ m/s)^2\\$

vf = 7.17 m/s

Now, for the time in air during downward motion we use the first equation of motion:

$v_f = v_i + gt_1\\7.17\ m/s = 0\ m/s + (9.8\ m/s^2)t_2\\t_2 = 0.73\ s$

(a)

Total Time of Flight = t = t₁ + t₂

t = 0.41 s + 0.73 s

t = 1.14 s

7 0

3 years ago

M=20kg F=10N d=25m Work done=?

fomenos

w=f×d

w=10N×25m

w=250Nm

5 0

3 years ago

A circuit consists of a 9.3-mH coil, a 16.0-V battery, a parallel combination of a 19-Ω resistor and a 6.0-Ω resistor, and a swi

Alla [95]

Answer:

τ = 0.00203 seconds

Explanation:

The time constant τ in a R-L circuit is given by

τ = L/R

First we have to find out the equivalent resistance of the circuit.

Since there is a parallel combination of 19 Ω and 6.0 Ω resistor

Req = 19*6/19+6

Req = 4.56 Ω

Now we can find out the time constant

τ = L/R

τ = 0.0093/4.56

τ = 0.00203 seconds

Therefore, the time constant of this circuit is 0.00203 seconds.

8 0

3 years ago