Ask question

Ask question

All categories

3 years ago

9

A force of 8800 N is exerted on a piston that has an area of 0.010 m^2. What is the force exerted by a second piston that has an

area of 0.040 m^2?

2 answers:

professor190 [17]3 years ago

8 0

Explanation:

It is given that,

Force on piston, F₁ = 8800 N

Area, $A_1=0.01\ m^2$

Area, $A_2=0.04\ m^2$

Let F₂ is the force exerted on the second piston. Using Pascal's law as :

Pressure at piston 1 = Pressure at piston 2

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}$

$F_2=\dfrac{F_1}{A_1}\times A_2$

$F_2=\dfrac{8800}{0.01}\times 0.04$

$F_2=35200\ N$

So, the force exerted by a second piston is 35200 N. Hence, this is the required solution.

AlekseyPX3 years ago

7 0

Answer:

the force exerted by a second piston is 35200 N

Explanation:

You might be interested in

The charge of an electron is

AlladinOne [14]

Proton positive; electron negative; neutron no charge<span>. </span>The charge<span> on the proton and </span>electron<span> are exactly the same size but opposite. The same number of protons and </span>electrons<span> exactly cancel one another in a neutral atom.
</span>
hoped it helped

6 0

3 years ago

An object has an acceleration of 18.0 m/s/s. If the net force

Xelga [282]

Answer:

to ejam is god oh yum2

Explanation:

4 0

3 years ago

In designing a backyard water fountain, a gardener wants to stream of water to exit from the bottom of one tub and land in a sec

mote1985 [20]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.

From the definition we know that the speed of a body can be described as a function of gravity and height

$V = \sqrt{2gh}$

$V = \sqrt{2*9.8*0.15}$

$V = 1.714m/s$

Then applying the kinematic equation of displacement, the height can be written as

$H = \frac{1}{2}gt^2$

Re-arrange to find t,

$t = \sqrt{2\frac{h}{g}}$

$t = \sqrt{2\frac{0.5}{9.8}}$

$t = 0.3194s$

Thus the calculation of the displacement would be subject to

$x = vt$

$x =1.714*0.3194$

$x = 0.547m$

Therefore the required distance must be 0.547m

4 0

3 years ago

What is reflection of light question mark write the laws of reflection of light

Zarrin [17]

Answer:

Reflection of light means the bouncing back of light in another direction after hitting a smooth polished surface

<h3><u>laws </u><u>of </u><u>reflection</u></h3>

1) Angie of incidence is equal to the angle of reflection

2) The nornal ray, reflected ray and the incident ray all lie in the same plane

3 0

3 years ago

In an experiment designed to measure the strength of a uniform magnetic field produced by a set of coils, electrons are accelera

Arlecino [84]

Answer:

the magnitude of the magnetic field is 8.704 x 10⁻⁴ T

Explanation:

Given;

potential difference, V = 278 V

radius of the circular path, r = 6.46 cm = 0.0646 m

charge of electron, q = 1.60218 × 10⁻¹⁹ C

mass of electron, m = 9.10939 × 10⁻³¹ kg

The magnitude of the magnetic field is given as;

$B = \frac{M_e*v}{q*r}$

where;

B is the magnitude of the magnetic field

$M_e$ is mass of the electron

v is velocity of the electron

r is the radius of the circular path

q is charge of the electron

Determine velocity of the electron from kinetic energy equation;

$K = \frac{1}{2} M_ev^2\\\\Vq = \frac{1}{2} M_ev^2\\\\v^2 = \frac{2qV}{M_e} \\\\v = \sqrt{\frac{2qV}{M_e}} = \sqrt{\frac{2*1.602*10^{-19}*278}{9.109*10^{-31}}} = 9.8886*10^{6} \ m/s$

the magnitude of the magnetic field:

$B = \frac{M_e*v}{q*r} \\\\B = \frac{(9.109*10^{-31})*(9.8886*10^6)}{(1.602*10^{-19})*(0.0646)} = 8.704*10^{-4} \ T$

Therefore, the magnitude of the magnetic field is 8.704 x 10⁻⁴ T

5 0

3 years ago