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taurus [48]
3 years ago
9

A force of 8800 N is exerted on a piston that has an area of 0.010 m^2. What is the force exerted by a second piston that has an

area of 0.040 m^2?
Physics
2 answers:
professor190 [17]3 years ago
8 0

Explanation:

It is given that,

Force on piston, F₁ = 8800 N

Area, A_1=0.01\ m^2

Area, A_2=0.04\ m^2

Let F₂ is the force exerted on the second piston. Using Pascal's law as :

Pressure at piston 1 = Pressure at piston 2

\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}

F_2=\dfrac{F_1}{A_1}\times A_2

F_2=\dfrac{8800}{0.01}\times 0.04

F_2=35200\ N

So, the force exerted by a second piston is 35200 N. Hence, this is the required solution.

AlekseyPX3 years ago
7 0

Answer:

the force exerted by a second piston is 35200 N

Explanation:

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