Question

A force of 8800 N is exerted on a piston that has an area of 0.010 m^2. What is the force exerted by a second piston that has an area of 0.040 m^2?

Answer 1

Explanation:

It is given that,

Force on piston, F₁ = 8800 N

Area, $A_1=0.01\ m^2$

Area, $A_2=0.04\ m^2$

Let F₂ is the force exerted on the second piston. Using Pascal's law as :

Pressure at piston 1 = Pressure at piston 2

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}$

$F_2=\dfrac{F_1}{A_1}\times A_2$

$F_2=\dfrac{8800}{0.01}\times 0.04$

$F_2=35200\ N$

So, the force exerted by a second piston is 35200 N. Hence, this is the required solution.

Answer 2

Answer:

the force exerted by a second piston is 35200 N

Explanation: