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2 years ago

Nancy ran a distance of 5km in 30 minutes. What is her speed in meters(m) per hour)h)

Physics

1 answer:

Virty [35]2 years ago

7 0

The speed of Nancy who ran a distance of 5 km in 30 minutes is 10000 meters(m) per hour(h).

<h3>What is the rate of speed?</h3>

The rate of speed is the rate at which the total distance is travelled in the time taken. Rate of speed can be given as,

$s=\dfrac{d}{t}$

Here, (d) is the distance travelled by the object and (t) is the time taken but the object to cover that distance.

Nancy ran a distance of 5 km in 30 minutes. There are 60 minutes in one hour. Thus, the time in hour for which Nancy ran is,

$t=\dfrac{30}{60}\\t=0.5\rm\; hr$

The meters in 5 kilometers is,

$d=5\times1000\\d=5000\rm\; m$

She ran 5000 kilometers in 0.5 hours. Thus, the speed of her is,

$s=\dfrac{5000}{0.5}\\s=10000\rm\; km/hr$

Thus, the speed of Nancy who ran a distance of 5 km in 30 minutes is 10000 meters(m) per hour(h).

Learn more about the rate of speed here:

brainly.com/question/359790

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The Earth's escape speed (the speed you need to get away forever) is about 40,000 kilometers per hour. Escape speed depends on t

Anvisha [2.4K]

The Moon s escape speed will be smaller than Earth's.

What is escape speed:

The minimum speed that is required for an object to free itself from the gravitational force exerted by a massive object.

The formula of escape speed is

$v = \sqrt{\frac{2GM}{R} }$

where

v is escape velocity

G is universal gravitational constant

M is mass of the body to be escaped from

r is distance from the center of the mass

we can say that,

Escape speed depends on the gravity of the object trying to hold the spacecraft from escaping.

we know that,

The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second.

since, v ∝ g

The Moon s escape speed will be smaller than Earth's.

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<u>brainly.com/question/15318861</u>

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5 0

2 years ago

A man jogs at a speed of 1.6 m/s. His dog waits 1.8 s and then takes off running at a speed of 3 m/s to catch the man. How far w

inessss [21]

Answer:

The dog catches up with the man 6.1714m later.

Explanation:

The first thing to take into account is the speed formula. It is $v=\frac{d}{t}$ , where v is speed, d is distance and t is time. From this formula, we can get the distance formula by finding d, it is $d=v\cdot t$

Now, the distance equation for the man would be:

$d_{man}=v_{man}\cdot t=1.6\cdot t$

The distance equation for the dog would be obtained by the same way with just a little detail. The dog takes off running 1.8s after the man did. So, in the equation we must subtract 1.8 from t.

$d_{dog}=v_{dog}\cdot (t-1.8)=3\cdot (t-1.8)$