Answer:
f1 = 12.90 Hz
Explanation:
To calculate the first harmonic frequency you use the following formula for n = 1:
( 1 )
It is necessary that the unist are in meters, then you have:
L: length of the string = 60cm = 0.6m
M: mass of the string = 0.05kg
T: tension on the string = 20 N
you replace the values of L, M and T in the expression (1) for getting f1:
Hence, the first harmonic has a frequency of 12.90 Hz
Answer:
When we double the angular velocity the maximum acceleration will changes by a factor of 4.
Explanation:
Given the angular frequency of the simple harmonic oscillator is doubled.
We need to find the change in the maximum acceleration of the oscillator.
Now, according to the problem, the angular frequency got doubled.
Let us plug . Then the maximum acceleration will be
We can see, when we double the angular velocity the maximum acceleration will changes by a factor of 4.