Question

g the eskimo pushes the same 50.0-kg sled over level ground with a force of 2.30 102 n exerted horizontally, moving it a distance of 5.55 m over new terrain. if the net work done on the sled is 2.50 102 j find the coefficient of kinetic friction.

Answer 1

The coefficient of kinetic friction is  ∪ = 3.699

What is Kinetic Energy?

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Given,

m = 50 kg

Force = 2.30 x 10^2 = 230N

Distance = 5.55m

Work done = 2.50 x 10^2 = 250 j

Using work energy principle:

F x d - ∪ x m x d = work done

230 x 5.55 -  ∪ x 50 x 5.55 = 250

1276.5 -  ∪ x 277.5 = 250

1276.5 - 250 =  277.5∪

1026.5 = 277.5 ∪

∪ = 1026.5 / 277.5

∪ = 3.699

Hence,  the coefficient of kinetic friction is ∪ = 3.699

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