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polet [3.4K]
1 year ago
6

g the eskimo pushes the same 50.0-kg sled over level ground with a force of 2.30 102 n exerted horizontally, moving it a distanc

e of 5.55 m over new terrain. if the net work done on the sled is 2.50 102 j find the coefficient of kinetic friction.
Physics
1 answer:
slava [35]1 year ago
6 0

The coefficient of kinetic friction is  ∪ = 3.699

What is Kinetic Energy?

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Given,

m = 50 kg

Force = 2.30 x 10^2 = 230N

Distance = 5.55m

Work done = 2.50 x 10^2 = 250 j

Using work energy principle:

F x d - ∪ x m x d = work done

230 x 5.55 -  ∪ x 50 x 5.55 = 250

1276.5 -  ∪ x 277.5 = 250

1276.5 - 250 =  277.5∪

1026.5 = 277.5 ∪

∪ = 1026.5 / 277.5

∪ = 3.699

Hence,  the coefficient of kinetic friction is ∪ = 3.699

To learn more about Kinetic energy click on the link

brainly.com/question/25959744

#SPJ4

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crimeas [40]

Answer:

Choice d. All three balls listed in choice a, b, and c have a momentum of 100\; \rm kg \cdot m \cdot s^{-1} each, same as that of the 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}. Assumption: all four balls are moving in the same direction.

Explanation:

The momentum p of an object is equal to the product of its mass m and its velocity v.

Momentum of a 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}:

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Similarly:

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Hence the conclusion that these balls have the same momentum.

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With light microscopy, if the objective lens (lens closest to the specimen) magnifies 40-fold, and the eyepiece lens magnifies 1
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The final magnification will be 400-fold or 400 times the original size of the object.

For magnifying smaller objects, a compound microscope is used.

A compound microscope consists of an objective and an eyepiece, whose diagram is shown in the adjoining image.

The lens  near  the object is called an objective and the other one is the eyepiece.

Let the magnification of the objective be m1

Let the magnification of the eyepiece be m2

The final magnification by the microscope, M, will be

M = m1 x m2

Putting the values in the above equation

M = 40 x 10

M= 400

Thus, the final magnification will be 400-fold or 400 times the original size of the object.

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