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Maksim231197 [3]
2 years ago
9

The mass of the boy is 35 kilograms. What is the force of friction that slowed him down?

Physics
1 answer:
pychu [463]2 years ago
3 0

Answer:

Newton's F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)

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In----- theory, the actual wishes that are threatening to the dreamers conscious awareness are disguised
Mandarinka [93]

Answer:

Unconscious wish fulfillment

Explanation:

Unconscious wish fulfillment

(In the unconscious wish fulfillment theory, the actual wishes of the dreamer that are threatening to the dreamer's conscious awareness are disguised.)

7 0
3 years ago
a test tube has a diameter of 3cm . how many turns would a piece of thread of length 90.42 make round test tube​
nadya68 [22]

Answer:

4.8 turns would be made around the tube

Explanation:

You need the circumference of the tube since it's just a lifted circle

2×pi×3=18.85

90.42/18.85=4.79

And round that to 4.8

6 0
3 years ago
Based on Archimedes' principle, we know that if an object displaces a given weight of water, then the object is being buoyed up
Virty [35]
True. If the amount displaced is more than the mass, it floats. If the amount is less than the mass, it will sink.
8 0
2 years ago
Read 2 more answers
-2 m
Nana76 [90]
Report this clown who put the first answer he’s trying to get your ip
4 0
2 years ago
A racing car reaches a speed of 42 m/s. It then begins a uniform negative acceleration, using its parachute and braking system,
NARA [144]

As per the question the initial speed of the car [ u] is 42 m/s.

The car applied its brake and comes to rest after 5.5 second.

The final velocity [v] of the car will be zero.

From the equation of kinematics we know that

                                         v=u+at [ here a stands for acceleration]

                                         0=42 +5.5a

                                         a =\frac{-42}{5.5} m/s^2

                                          a= -7.64 m/s^2

Here a is taken negative as it the car is decelerating uniformly.

We are asked to calculate the stopping distance .

From equation of kinematics we know that

                                              S=ut+\frac{1}{2} at^2  [here S is the distance]

                                                      = 42*5.5 +\frac{1}{2} [-7.64] [5.5]^2 m

                                                       =115.445 m      [ans]  

8 0
2 years ago
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