Answer:
The speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.
Explanation:
To find the speed of light in air and in polystyrene we need to use the following equation:
Where:
: is the speed of light in the medium
n: is the refractive index of the medium
In air:
In polystyrene:
Therefore, the speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.
I hope it helps you!
Answer:
True
Explanation:
Magnitude is the "value" the greater the value the greater the force is and vice versa
Answer:
F = 96.11 N
friction force =33.48 N
Explanation:
given,
mass of block M = 7.50 kg
acceleration = 3 m/s²
µ s = 0.443 and µ k = 0.312
angle with the horizontal = 25°
the component of force along the incline is F cos theta
normal reaction ,


N = 66.68+ .423 F
for the mass


0.906 F - 0.132 F - 31.09 - 20.8 = 22.5
0.774F = 74.39
F = 96.11 N
normal force ,
N = 66.68 + .423×96.11
=107.33 N
friction force = .312 × N
= 0.312× 107.33
friction force =33.48 N
1) Focal length
We can find the focal length of the mirror by using the mirror equation:

(1)
where
f is the focal length

is the distance of the object from the mirror

is the distance of the image from the mirror
In this case,

, while

(the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:

from which we find

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.
3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.
4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is: