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Aliun [14]
3 years ago
11

Hi :) In a pendulum experience , what affects the period & explanation too? Thank you sm :))

Physics
1 answer:
stich3 [128]3 years ago
4 0

Answer:

T=2π\sqrt{l/g}  (simple pendulum)

length of the string  and gravity mainly effect the pendulum period

Explanation:

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What is the speed of light (in m/s) in air? (Enter your answer to at least four significant figures. Assume the speed of light i
jenyasd209 [6]

Answer:

The speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

Explanation:

To find the speed of light in air and in polystyrene we need to use the following equation:

c_{m} = \frac{c}{n}

Where:

c_{m}: is the speed of light in the medium

n: is the refractive index of the medium

In air:

c_{a} = \frac{c}{n_{a}} = \frac{2.997 \cdot 10^{8} m/s}{1.0003} = 2.996 \cdot 10^{8} m/s

In polystyrene:

c_{p} = \frac{c}{n_{p}} = \frac{2.997 \cdot 10^{8} m/s}{1.6} = 1.873 \cdot 10^{8} m/s  

Therefore, the speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

I hope it helps you!

8 0
3 years ago
TRUE OR FALSE! PLZ HELP
Ksju [112]

Answer:

True

Explanation:

Magnitude is the "value" the greater the value the greater the force is and vice versa

5 0
2 years ago
A block with mass M = 7.50 kg is initially moving up the incline with speed v 0 and is increasing speed with acceleration a = 3
valina [46]

Answer:

F = 96.11 N

friction force =33.48 N

Explanation:

given,

mass of block M = 7.50 kg

acceleration = 3 m/s²

µ s = 0.443 and µ k = 0.312

angle with the horizontal = 25°

the component of force along the incline is F cos theta

normal reaction ,

N = mg cos \theta + F sin \theta

N = 7.5\times 9.81\times cos25^0 + F sin 25^0

N = 66.68+ .423 F

for the mass

F cos \theta - mg sin \theta - \mu_k\ N = ma

F cos 25^0 - 7.5\times 9.81\times sin 25^0 - 0.312\times ( 66.68+ .423 F) = 7.5\times 3

0.906 F - 0.132 F - 31.09 - 20.8 = 22.5

0.774F = 74.39

F = 96.11 N

normal force ,

N = 66.68 + .423×96.11

  =107.33 N

friction force = .312 × N

                     = 0.312× 107.33

friction force =33.48 N

                 

3 0
3 years ago
Which statement describes how Earth compares to the moon? Earth has more inertia than the moon. The moon has more gravitational
Juliette [100K]

Answer

Earth has more inertia than the moon.

6 0
3 years ago
Read 2 more answers
An object is placed 18 cm in front of spherical mirror.if the image is formed at 4cm to the right of the mirror, calculate it's
ivolga24 [154]
1) Focal length

We can find the focal length of the mirror by using the mirror equation:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i} (1)
where 
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
\frac{1}{f}= \frac{1}{18 cm}- \frac{1}{4 cm}=- \frac{7}{36 cm}
from which we find
f=- \frac{36}{7} cm=-5.1 cm

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
r=2f=2 \cdot 5.1 cm=10.2 cm
3 0
4 years ago
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