All categories

3 years ago

Identify the areas on the image where the force of repulsion is the least.

Physics

2 answers:

astra-53 [7]3 years ago

6 0

Answer:

lower two magnets is the correct answer I believe

aalyn [17]3 years ago

4 0

Answer:

The central blue square in between the lower pair of magnet has the least force of repulsion.

Explanation:

We can explain this using the dual nature of magnets.

Each magnet must have two poles namely:

-North pole

-South pole

We assume that the magnetic lines of forces enters from south pole and leaves from the north pole.

When brought together, like poles repel each other while opposite poles attract each other.

In the picture, the lower two magnets have opposite poles facing each other, hence the force of repulsion is minimum there and the force of attraction is maximum.

You might be interested in

Several large firecrackers are inserted into the holes of a bowling ball, and the 6.3 kg ball is then launched into the air with

Anni [7]

Answer

given,

mass of the ball = 6.3 kg

speed of the ball = 10.4 m/s

angle made with horizontal = 43°

m_a = 1.8 kg v_a = 2.2 m/s

m_b = 1.6 kg v_b = 1.8 m/s

mass of third particle = 6.3 - 1.8 - 1.6

= 2.9 kg

u cos θ = 10.4 x cos 43° = 7.61 m/s

by using conservation momentum along x-axis

6.3 x 7.61 = 1.8 × (-2.2) + 0 + 1.6 × V₃ₓ

V₃ₓ = 32.44 m/s (toward right)

by using conservation momentum along y-axis

0 = 0 + 1.6 x 1.8 + 1.6 × V₃y

V₃y = -1.8 m/s (indicate downward)

velocity of the third particle

$v = \sqrt{32.44^2 + (-1.8)^2}$

v = 32.49 m/s

$tan \theta = \dfrac{-1.8}{32.44}$

$\theta = tan^{-1}(\dfrac{-1.8}{32.44})$

θ = 3.176° (downward with horizontal)

4 0

3 years ago

Identify the scenario below as to whether they increase, decrease, or not change the frequency in which a string vibrates and th

telo118 [61]

Answer:1. Increase 2. Decrease 3. Decrease

Explanation:

4 0

3 years ago

Find the net force on q3. Include the direction (+ or -). (Unit = N) PLS HELP!

NNADVOKAT [17]

Answer:

Explanation:

First of all we shall find out net electric field at q₃ due to both of the remaining charges .

electric field due to charge Q = k Q / r² where k = 9 x 10⁹ Q is amount of charge and r is distance of point

electric field due to charge 105 x 10⁻⁶ C

= 9 x 10⁹ x 105 x 10⁻⁶ / .95²

= 1.047 x 10⁶ N/C .

It will act away from q₂

electric field due to charge 53 x 10⁻⁶ C

= 9 x 10⁹ x 53 x 10⁻⁶ /( .5+.95)²

= 0.227 x 10⁶ N/C .

It will act towards q₁

These fields are in opposite direction so

net field E = 0.82 x 10⁶ N/C.

It will act away from q₂ .

Force on q₃ due to net field

= q₃ E

= 88 x 10⁻⁶ x 0.82 x 10⁶

= 72.16 N

The direction of this field will be towards q₂ because force on negative charge in a field is always in a direction opposite to the direction of the field.

8 0

3 years ago

Take the direction of east to be positive and west to be negative.

Westkost [7]

hope this helped anyone good luck!!!!

8 0

3 years ago

Read 2 more answers

10,000 W of power is used to move a spoon for 10 s. How much work is done on the spoon?

bixtya [17]

Answer:

The work done is 100,000 Joule

Explanation:

Work and Power

Work is the amount of energy transferred by a force.

If both the force F and displacement s are parallel, then we can use the formula:

W = F.s

Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.

The power can be calculated as:

$\displaystyle P=\frac {W}{t}$

Where W is the work and t is the time.

We know the power needed to move a spoon is P=10,000 Watt and it took a time of t=10 s. The work done on the spoon is calculated by solving for W:

W = Pt

W = 10,000 Watt * 10 sec

W = 100,000 Joule

The work done is 100,000 Joule

6 0

3 years ago

Identify the areas on the image where the force of repulsion is the least.​

Identify the areas on the image where the force of repulsion is the least.