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the answer is A.
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Answer:
angular acceleration is -0.2063 rad/s²
Explanation:
Given data
mass m = 95.2 kg
radius r = 0.399 m
turning ω = 93 rpm
radial force N = 19.6 N
kinetic coefficient of friction μ = 0.2
to find out
angular acceleration
solution
we know frictional force that is = radial force × kinetic coefficient of friction
frictional force = 19.6 × 0.2
frictional force = 3.92 N
and
we know moment of inertia that is
γ = I ×α = frictional force × r
so
γ = 1/2 mr²α
α = -2f /mr
α = -2(3.92) /95.2 (0.399)
α = - 7.84 / 37.9848 = -0.2063
so angular acceleration is -0.2063 rad/s²
Hi there!
Recall the equation for kinetic energy:
KE = Kinetic energy (J)
m = mass (kg)
v = velocity (m/s)
Plug in the given values:
The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².
<h3>How to calculate acceleration?</h3>
Acceleration is change of velocity with respect to time (can include deceleration or changing direction).
The acceleration of a body can be calculated by using the following expression;
a = F/m
Where;
- a = acceleration (m/s²)
- F = force (N)
- m = mass (kg)
According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:
a = 4N ÷ 2.55kg
a = 1.57m/s²
Therefore, 1.57m/s² is the acceleration of the object.
Learn more about acceleration at: brainly.com/question/28767690
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