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leva [86]
3 years ago
9

Force exerted by a person or object is called

Physics
1 answer:
vaieri [72.5K]3 years ago
6 0

Force exerted by a person or thing is called _____ force. applied. A change in the speed or direction of an object is called. acceleration. Force is a vector.

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A typical electric oven has two separate heating elements: one on top and one on the bottom. The bottom element is used for baki
Hunter-Best [27]

Answer:

Convection and Radiation mechanisms carry most of the heat

Explanation:

This is because Convection proceeds strongy as heated air rises from the hot element while Radiation is also strong, although the material of the cooking pots will how effective it is.

3 0
3 years ago
A
kotegsom [21]

Answer:

conservative

Explanation:

Nonconservative force is the force that depends on a path, however conservative does not depend on a path and it is not associated with the potential energy. When the work is done by an unconservative force, mechanical energy is added or removed. Friction is the best example for a non-conservative force. When these non-conservative forces are acting, the mechanical energy changes but these are not preserved.

hope this helped!

3 0
2 years ago
An object with a velocity of 15 m/s and has a kinetic energy of 1125 J, what is the mass of the object?
BARSIC [14]

Answer:

K= 1/2 mv^2

m= 2K/v^2= 2250/ 225= 10 Kg

6 0
2 years ago
Why wont the baby go to sleep? and why is he crying and pulling at his ears?
stepladder [879]

Answer:

Babies often struggle to go to sleep sometimes warm milk and sooting sounds help babies sleep

Explanation:

8 0
3 years ago
Read 2 more answers
A car tire contains 0.0380m3 of air at a pressure of 2.20×105N/m2 (about 32 psi). How much more internal energy does this gas ha
emmasim [6.3K]

Answer:

\Delta U = 11305 J

Explanation:

As per ideal gas equation we know that

PV = nRT

here we know that

P = 2.20 \times 10^5 Pa

V = 0.0380 m^3

now we have

nRT_1 = (2.20 \times 10^5)(0.0380) = 8360 J

now for other case at zero gauge pressure we have

P = 1.01 \times 10^5 Pa

V = 0.0380 m^3

we have now

nRT_2 = (1.01 \times 10^5)(0.0380) = 3838 J

now the difference in internal energy of air is given as

\Delta U = \frac{5}{2}nR\Delta T

\Delta U = \frac{5}{2}(8360 - 3838)

\Delta U = 11305 J

6 0
3 years ago
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