So exg
feet to inches or vice verca
so 12in=1ft
so
3 ft to in
conversion factor 12in/1ft
multiply 3 with 12in/1ft
ft units cancel
3 times 12=36=answer
convert 48 in to feet
1 ft=12 in
conversion factor 1ft=12in
multiply 48in with 1ft/12in
in cancel
48/12=4 ft
Answer:
The mass of the bag of sand must be equal to 
Step-by-step explanation:
<u><em>The complete question is</em></u>
In the opening scene of the movie Raiders of the Lost Ark, Indiana Jones replaces a golden statue with a bag of sand. The platform on which the statue is placed is designed to detect the mass of the statue. If the bag of sand has a different mass than the statue, then a mechanism triggers and destruction ensues.
The density of gold is about 20 g/ cm^3 . The density of sand can be estimated at 2.5 g/cm^3. The gold statue can be modeled as a cylinder with height 25 cm and radius 8 cm.
In terms of pi, what is the mass of sand Indiana Jones needs to avoid triggering the mechanism?
step 1
Find the volume of the gold statue
The volume of a cylinder is equal to
substitute the given values
step 2
Find the mass of gold
Remember that the mass is equal to multiply the density by the volume
so
step 3
what is the mass of sand Indiana Jones needs to avoid triggering the mechanism?
we know that
The mass of the bah of sand must be equal to the mass of the statue
therefore
The mass of the bag of sand must be equal to
12A+8W > 343 represents the number of minutes the robot filters air A and water W to filter more than 343 liters of air and water.
If the robot filters air for 20 minutes and water for 15 minutes, plugging A as 20 and W as 15, let us check if the equation is true or not.
Checking left side:
12A + 8W = 12(20) +8(15)
240+ 120 = 360
Checking right side: 343
12A+8W > 343
360>343
True.
So the robot meets the first expectation.
Let us check for second equation:
3A+4W < 49
Left side : 3A +4W = 3(20) +4(15) = 60 +60 =120
Right side is 49
comparing left and right side:
3A+4W < 49
120<49
False.
So the robot does not meet the second expectation.
Answer:
C. Reflection over x- axis, down 6 right 3
Step-by-step explanation:
I started this and got distracted and never finished and it timed out. Focus Dean.
It's not the best graph; I assume the origin is the apparent origin and the y axis numbers go with the line above them.
This graph is M(V), M(V) is mass in kg of bucket with water volume V in liters
a) the mass of an empty bucket
That's the y intercept, M(0), eyeballing it around .7 kg
Answer: .7 kg
b) the mass of the bucket containing 1 liter of liquid
That's M(1), looks like 1.3 or so
Answer: 1.3 kg
c) the mass of one liter of liquid
That's the difference, M(1)-M(0), about .6 kg. We can get a better estimate from a longer slope, say (.5,1) to (3,3), (3-1)/(3-.5) = .8 kg.
Answer
: 0.8 kg
d) the volume of the liquid in the bucket, if the total mass of bucket with the liquid is 3 kg.
Solve M(V)=3
That has a solution from the graph V=3.
Answer: 3 liters
