Answer:
Can i See A Photo of the diagram.
Explanation:
The calculated electric field is 3.0 N/C
<u>Explanation:</u>
The electric field is described only as the charge that it produces and is unique at every point in space. In particular, the electric field E is defined as the ratio of Coulomb forces to test charge. It can express as follows,
Where, F is the electrostatic (or Coulomb) force exerted on the positive test charge q. It is clear that E acts in the same direction of force. It is also assumed that q is so small and will not change the distribution of the charge generated by the electric field. It can express by a unit Newton per Coulomb (N / C).
Here, the given data, q = 2.0 C and F = 6.0 N. So, the electric field would be,
Answer:
1)m=89.01 g
2)V(max) = 97.3 cm/s
Explanation:
Given that
K= 15 N/m
The maximum amplitude ,A=7.5 cm = 0.075 m
Given that 31 oscillations in 15 seconds ,this means that frequency f
f=\dfrac{31}{15}
f=2.066 Hz
lets take mass of the ball = m kg
m=0.08901 kg
m=89.01 g
The maximum speed
V(max)= ω x A
ω = 2π f= 2 x π x 2.066 = 12.98 rad/s
V(max) = 12.98 x 0.075 =0.973 m/s
V(max) = 97.3 cm/s
J.J. Thomson discovered the electron, leading to the Plum Pudding model