I looked up the question and got D- a vacuum
Answer:
2*10^-<em>5</em>
Explanation:
<em>B=</em><em>I</em><em>L</em>
<em>I=</em><em>B</em><em>/</em><em>L</em>
<em>I=</em><em>0</em><em>.</em><em>0</em><em>0</em><em>2</em><em>0</em><em>*</em><em>1</em><em>0</em><em>^</em><em>-</em><em>4</em><em>/</em><em>1</em><em>0</em>
<em>I=</em><em>2</em><em>*</em><em>1</em><em>0</em><em>^</em><em>5</em>
Answer:
The maximum no. of electrons- 
Solution:
As per the question:
Maximum rate of transfer of charge, I = 1.0 C/s
Time, t = 1.0 h = 3600 s
Rate of transfer of charge is current, I
Also,

Q = ne
where
n = no. of electrons
Q = charge in coulomb
I = current
Thus
Q = It
Thus the charge flow in 1. 0 h:

Maximum number of electrons, n is given by:

where
e = charge on an electron = 
Thus

Answer:

Explanation:
The x- and y- components of the velocity vector can be written as following:


Since the angle θ and the magnitude of the velocity is given, the vector representation can be written as follows:

Answer:

Explanation:
density of the solid box material = 
density of the liquid material = 
Given that
solid box floats with two thirds of its volume submerged in a liquid
let V be the volume of the box
then,

⇒
so, the ratio of densities of solid and and the liquid is 2/3