What are some ways houses along the coastlines can protect themselves from storm surges?
1 answer:
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Answer:
Heat capacity, Q = 38500 Joules
Explanation:
Given the following data;
Mass = 2 kg
Initial temperature, T1 = 30°C
Final temperature, T2 = 80°C
Specific heat capacity of copper = 385 J/Kg°C
To find the quantity of heat required;
Mathematically, heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
M represents the mass of an object.
C represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 80 - 30
dt = 50°C
Substituting the values into the formula, we have;
Heat capacity, Q = 38500 Joules
Answer:
The heat is 10458 J and 15480 J.
Explanation:
Given that,
Temperature T₁ = 404 K
Temperature T₂ = 298 K
Work done = 2740 J
If the temperature T₁ =298 k
Temperature T₂ = 245 K
We need to calculate the heat
Using efficiency formula
...(I)
We need to calculate the efficiency
Using formula of efficiency
Put the value of efficiency in equation (I)
Again, we need to calculate the efficiency
We need to calculate the heat
Using equation (I)
Hence, The heat is 10458 J and 15480 J.